Answer:
volume of air breath = 495.75 mL per min
Explanation:
given data
oxygen required = 2.4 × 10² mL / Min = 240 mL
inhaled air = 20 %
exhaled air = 16 %
to find out
volume of air per breath
solution
we know here that breathes 12 time every minute
and we consider here air breath = y per min
we know oxygen remain in body = 20 % - 16 % = 4%
and required 12 time air breath
so air required = 240 / 12 = 19.83 mL
so oxygen breath equation will be
y × 4% = 19.83
y = 19.83 / 0.04
y = 495.75
so volume of air breath = 495.75 mL per min
Answer:
M = 3.485 kg
m = 1.605 kg
Explanation:
F = 0.98 x 10^-8 N
r = 19.5 cm = 0.195 m
M + m = 5.09 kg ...... (1)
By use of Newton's gravitational law
F = G m1 m2 / r^2
0.98 x 10^-8 = 6.67 x 10^-11 x M x m / (0.195)^2
M x m = 5.59
M - m = 1.88 .........(2)
By solving the equation (1) and equation (20, we get
M = 3.485 kg
m = 1.605 kg
B, the light should be travelling out of the optically dense medium to the optically less dense medium.
were d to read "... is greater than the critical angle" I'd agree with it. But it doesn't read that way ...
Which leaves b as the only one which I think is true. Which I find a bit odd.
Out of interest, TIR is often used in piping light down optical fibres, among many other applications.
Answer:
Its duration is 1.85*10⁻³ s or 1.85 ms
Explanation:
The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).
The intensity of electric current is expressed as:
where:
I: Intensity expressed in Amps (A)
Q: Electric charge expressed in Coulombs (C)
t: Time expressed in seconds (s)
Being:
Replacing:
Solving:
19500 A*t= 36 C
t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)
<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>