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EleoNora [17]
3 years ago
15

A shell is fired from the ground with an initial speed of 1.60 × 103 m/s (approximately five times the speed of sound) at an ini

tial angle of 51.0 ◦ to the horizontal. The acceleration of gravity is 9.81 m/s 2 . a) Neglecting air resistance, find the shell’s horizontal range. Answer in units of m.
Physics
1 answer:
Volgvan3 years ago
6 0

Answer:

The horizontal range will be 2.55\times 10^5m

Explanation:

We have given initial speed of the shell u = 1.6\times 10^3m/sec

Angle of projection = 51°

Acceleration due to gravity g=9.8m/sec^2

We have to find maximum range

Horizontal range in projectile motion is given by

R=\frac{u^2sin2\Theta }{g}=\frac{(1.60\times 10^3)^2sin(2\times 51^{\circ})}{9.81}=2.55\times 10^5m

So the horizontal range will be 2.55\times 10^5m

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