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Oksi-84 [34.3K]
3 years ago
6

Which of these forces determines the chemical properties of an atom? friction force nuclear force gravitational force electrical

force none of these?
Physics
1 answer:
zysi [14]3 years ago
3 0
The answers is an electrical force.
Under normal conditions, atoms interact with each other via electrons that are furthest away from the nucleus. These electrons from the what is called the outer shell of the atom, electrons from the outer shell that can participate in chemical reactions are called valence electrons.

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An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char
ArbitrLikvidat [17]

Answer:

Part a)

W = 1.58 \times 10^{-20} J

Part b)

v = 1.86 \times 10^5 m/s

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = 4.00 \times 10^{-12} C/m^2

now the electric field is given as

E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}

E = 0.225 N/C

Now acceleration of an electron due to this electric field is given as

a = \frac{eE}{m}

a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}

a = 3.97 \times 10^{10}

Now work done on the electron due to this electric field

W = F.d

d = 0.470 - 0.03

d = 0.44 m

So work done is given as

W = (ma)(0.44)

W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)

W = 1.58 \times 10^{-20} J

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

W = \frac{1}{2}mv^2 - 0

1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2

v = 1.86 \times 10^5 m/s

7 0
3 years ago
Why is the sky blue and doesn't change color
Softa [21]

The statement is <u>false</u> because the sky <u>can change </u>colors during sunsets, sun rises, etc. The sky is not always blue.

7 0
3 years ago
One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat
marin [14]

Answer:

B. 2.77 x 10^{-4} N

Explanation:

The required force can be calculated by:

F = \frac{Kq_{1}q_{2}  }{d^{2} }

Where F is the force between the particles, K is the coulomb's constant (9 x 10^{9} Nm^{2}/C^{2}), q_{1} is the charge on the first particle, q_{2} is the charge on the second particle and d^{2} is the distance between the particles.

So that:

F = \frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9}  }{(0.015)^{2} }

  = \frac{6.2307*10^{-8} }{(2.25*10^{-4} }

  = 2.7692 x 10^{-4}

 The force between the particles is 2.77 x 10^{-4} N.

3 0
2 years ago
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.
Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

\sum F=m.a

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N

5 0
3 years ago
Check my answer(there’s one above) I really just chose my best guess on this.for the ones below, can you provide a simple explan
almond37 [142]

#1

For closed pipe the fundamental frequency will be given as

f = \frac{v}{4L}

153 = \frac{340}{4L}

L = 0.56 m

L = 55 cm

#2

For open pipe the wavelength for Nth harmonic will be given as

n \times \frac{\lambda}{2} = L

\lambda = \frac{2L}{n}

#3

for a closed pipe the frequency is given as

f = \frac{nv}{4L}

here for third harmonic n = 3

f = \frac{3v}{4L}

now plug in all values

235 = \frac{3\times 340}{4L}

L = 1.09 m

L = 109 cm

#10

since in the given figure there are three complete loops

so in this case the <em>number of harmonics are THREE</em>

3 0
3 years ago
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