Electrolytes are substances that produce ions when they dissolve in water.
What are electrolytes?
When some substances are dissolved in water, they undergo physical or chemical changes, creating ions in solution. These substances form an important class of compounds called electrolytes. Substances that do not release ions when dissolved are called non-electrolytes. A substance is said to be a strong electrolyte if the physical or chemical process that produces ions is inherently 100% efficient (all dissolved compounds produce ions). A solute is said to be a weak electrolyte if only a relatively small portion of the solute undergoes ion production processes.
By measuring the electrical conductivity of aqueous solutions containing substances, substances can be identified as strong, weak, or non-electrolyte. To conduct electricity, a substance must contain free-moving charged species. The best known is the conduction of electricity through metal wires. In this case, the mobile charged unit is the electron.
Therefore, Electrolytes are substances that produce ions when they dissolve in water.
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Answer:
What do <u>YOU</u> think?
Explanation:
This question is asking for an opinion. The word should is included.
Enthalpy is energy of bonds broken - energy of bonds formed. Here, the NH3 and O2 are broken and H2O and NO are formed. So the energy to break the NH3 bonds is 3 times the amount of energy it takes to break a N-H single bond (because there are three of them in a NH3 molecule) and then multiplied by 4 because there are four particles.
So the energy of the bonds broken is 12x the energy to break a N-H single bond plus 5x the amount of energy to break an O—O double bond (you don’t multiply this by anything because in each O2 molecule there is only one bond).
The energy of the bonds formed is 6*2 = 12 Times the amount of energy for a O-H single bond plus 4 times the amount of energy required to break a N—O double bond.
Subtract energy of bonds broken - energy of bonds formed and this is the change in enthalpy.
To know what type of bond it is, draw the Lewis structure.
Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
Answer:
(D) Neither I nor II
Explanation:
The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .
The pallet form of NaOH ( solid form ) absorbs carbon dioxide gas from the atmosphere but NaOH in solution form does not absorb carbon dioxide .
Hence option D ) is right choice .
