Actually its the second and fourth one for sure! If you just put one it only gives parcel credit. ;-;
Answer:
216.0cm³ of ore must be processed
Explanation:
First, we need to know how many grams of gold we need to obtain $100.00
<em>Mass of gold to obtain $100.00:</em>
$100.00 gold * (1 troy oz / $818) = 0.122 troy oz
0.122 troy oz * (1.0lb / 14.6troy oz) = 8.37x10⁻³ lb
8.37x10⁻³ lb * (454g / 1lb) =
3.80g of gold we need to obtain $100.00
Now, the ore contain 0.22g of gold in 100g and the density of the ore is 8.0g/cm³. We can solve the cubic centimeters to obtain $100.00:
<em>Cubic centimeters of ore:</em>
3.80g Gold * (100g Ore / 0.22g Gold) = 1727.9g of Ore
1727.9g Ore * (1cm³ / 8.0g Ore) =
<h3>216.0cm³ of ore must be processed</h3>
Answer: 1,000 grams
Explanation: I learned about this once
The grams of FeO that would be needed to make 234.2 grams of Fe is
1204.42 grams
<u><em> calculation</em></u>
4 FeO → Fe₃O₄ +Fe
Step 1: find the moles of fe
moles = mass /molar mass
from periodic table the molar mass of Fe = 56 g/mol
moles = 234.2 g/56 g/mol = 4.182 moles
Step 2: use the mole ratio to determine the moles of FeO
FeO: Fe is 4:1 therefore the moles of FeO =4.182 moles x4 =16.728 moles
Step 3: find the mass of FeO
mass = moles x molar mass
The molar mass of FeO = 56 +16 = 72 g /mol
mass = 16.728 moles x 72 g/mol= 1204.42 grams
