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Ronch [10]
3 years ago
9

PLEASE HELP, I don’t know how to do this

Physics
1 answer:
MrRa [10]3 years ago
7 0

Explanation:

7) Given:

v₀ = 2.0 m/s

v = 0 m/s

t = 3.00 s

Find: Δx

Acceleration isn't included in the problem, so use a kinematic equation that doesn't involve a.

Δx = ½ (v + v₀) t

Δx = ½ (0 m/s + 2.0 m/s) (3.00 s)

Δx = 3.0 m

8) Given:

v₀ = 0 m/s

v = 5 m/s

t = 4 s

Find: a

Displacement isn't included in the problem, so use a kinematic equation that doesn't involve Δx.

v = at + v₀

5 m/s = a (4 s) + 0 m/s

a = 1.25 m/s²

9) Given:

v_avg = Δx / t

0.5 m/s = 8 m / t

t = 16 s

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The location of the point F that partitions a line segment from D to E (\overline{DE}), that goes from <u>negative 4</u> to <u>positive 5,</u> into a 5:6 ratio is fifteen halves (option 4).  

We need to calculate the segment of the line DE to find the location of point F.

Since point D is located at <u>negative -4</u> and point E is at <u>positive 5</u>, we have:

\overline{DE} = E - D = 5 - (-4) = 9

Hence, the segment of the line DE (\overline{DE}) is 9.

Knowing that point F partitions the line segment from D to E (\overline{DE}) into a <u>5:6 ratio</u>, its location would be:

F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2}  

Therefore, the location of point F is fifteen halves (option 4).

Learn more about segments here:

  • brainly.com/question/24472171?referrer=searchResults
  • brainly.com/question/13270900?referrer=searchResults

       

I hope it helps you!

5 0
3 years ago
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What is electrical circuit​
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Path for transmitting electric current. An electric circuit includes a device that gives energy to the charged particles constituting the current, such as battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines
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A solid metal sphere with radius 0.430 m carries a net charge of 0.270 nC . Part A Find the magnitude of the electric field at a
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Answer:

8.46 N/C

Explanation:

Using Gauss law

E=\frac {kQ}{r^{2}}

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge

Here, K is Coulomb's constant whose value is 9\times 10^{9} Nm^{2}/C^{2}

r = 0.43 + 0.106 = 0.536 m

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4 years ago
An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second squared in the direction
leva [86]

Answer:

6 m/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 4 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =?

The final velocity of the object can obtained as shown below:

v² = u² + 2as

v² = 4² + (2 × 2 × 5)

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Take the square root of both side.

v = √36

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Therefore, the final speed of the object is 6 m/s.

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Answer:

ORGANISMS

Explanation:

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