A 4350 kg truck, driving 7.39 m/s, runs into the back of a stationary car. After the collision, the truck moves 4.55 m/s and the
1 answer:
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Answer:
<em>W=700 Joule</em>
Explanation:
<u>Physics Work </u>
Is the dot product of the force vector by the displacement vector
When both the force and the displacements are pointed in the same direction, the formula reduces to its scalar version
The weightlifter is applying a net force of 350 N to lift the weights a distance of 2 m, thus the net work done is
Answer : The correct option is, (B) -5448 kJ/mol
Explanation :
First we have to calculate the heat required by water.
where,
q = heat required by water = ?
m = mass of water = 250 g
c = specific heat capacity of water =
= initial temperature of water = 293.0 K
= final temperature of water = 371.2 K
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy of combustion of octane.
where,
= enthalpy of combustion of octane = ?
q = heat released = -81719 J
n = moles of octane = 0.015 moles
Now put all the given values in the above formula, we get:
Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.