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3 years ago

How many liters of 0.85 M HCI solution would react completely with 3.5 moles Ca (OH)2?

1 answer:

7 0

Ca(OH)2+2HCL=CaCl2+2H2O
So the molar ratio between ca(oh)2 and hcl is 1 is to 2
Thus with each mole of ca(oh)2 the 2 moles of hcl will react
As a result for a complete reaction we need 7 mole of HCL
Molarity of hcl is 0.85
so number of litres of hcl needed would be 8.2 as
number of moles of hcl=8.2x0.85=7moles
So
ANSWER IS B 8.2 L OF HCL

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The formula for mole fraction is:

$mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}$ -(1)

The solubility of oxygen gas = 1.0 mmol/L (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

$1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol$

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

$Density = \frac{mass}{volume}$

$Mass = 1.0 g/ml\times 1000 mL = 1000 g$

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = $\frac{1000 g}{18 g/mol} = 55.55 mol$

Substituting the values in formula (1):

$mole fraction = \frac{0.001}{55.55+0.001}$

$mole fraction = 1.8\times 10^{-5}$

Hence, the mole fraction is $1.8\times 10^{-5}$ .

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3 years ago

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Here,

q is amount of energy released L is heat of fusion ( $334 J/g$ ) m is mass of water Put all the given values in equation (1)

$q= 334 J/g \times 65.8 g$

$q= 21977.2 Joules$ ≅ $21977 Joules$

$q= 21977 Joules$

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