1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zavuch27 [327]
3 years ago
6

Can someone please help me

Chemistry
1 answer:
Alona [7]3 years ago
5 0

Answer:

Potassium iodide increases the decomposition rate of hydrogen peroxide.

Explanation:

Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.

You might be interested in
The individual components of a solution_____.
Misha Larkins [42]
Its been awhile since I've dabbled in chemistry, but i do know that A isnt the answer because the question says solution, not mixture. This looks somewhat like a trick question, it says individual components, so the answer would be C. This is because the individual components do react to form a compound. B and D would be true if it didnt say individual components, so the question is basically focusing on only one ingredient, not the whole solution. Answer: C
4 0
3 years ago
Read 2 more answers
What is a common reason for observing an increased chemical shift of a c-h proton
stira [4]

Deshielding due to an electronegative element close by is the common reason for observing increased chemical shift of a c-h proton

<h3>What is a chemical shift? </h3>

The resonance frequency of a proton in relation to a standard compound is represented by chemical shift. Chemical shift, which is measured in ppm and is represented by the sign (δ),  (parts per million).The chemical shift in a proton NMR spectrum provides details about the targeted proton's chemical surroundings. The structure of the investigated substance, especially electronegative components or effects, has a significant impact on the chemical shift value. Electronegative elements' ability to remove electron density from the proton, which raises the chemical shift value, is one explanation for this. The proton is more exposed to the magnetic field that is being applied externally as a result of this process, which is referred to as de-shielding.

To learn more about limbic system visit:

brainly.com/question/14788457

#SPJ4

3 0
1 year ago
How should data be organized?
natima [27]
It should be organized in people
6 0
2 years ago
Read 2 more answers
A temperature of 37C is equivalent to a temperature of
ss7ja [257]
Answer 98.6 Fahrenheit
8 0
3 years ago
Read 2 more answers
What is the area on the earth's surface directly above where an earthquake originates?
Natalija [7]

Answer:

The epicenter

5 0
2 years ago
Other questions:
  • An atom has the following electron configuration.
    11·2 answers
  • How do I balance chemical equations ?<br>​
    9·1 answer
  • Explain the 4 methods of separating mixtures
    7·1 answer
  • Lizzy lost 2.3 lbs of water due to sweating during baseball practice. How much energy is absorbed from Lizzy's body for this pro
    6·1 answer
  • Alana summarized what happens when a ball sitting on top of a grassy hill rolls down the hill.
    7·1 answer
  • If D+2 would react with E-1, what do you predict to be the formula?
    9·1 answer
  • The percentage by mass of Br in the compound
    5·2 answers
  • Hey<br>here to help and to serve
    14·2 answers
  • How many miles could you drive for $7.90 if the gas mileage of your car is 14km/liter of gas and the price is $1.29/gal? (1.61km
    13·1 answer
  • What is the F-Xe angle in the molecule - F; Xe * F_{2} (Xe has three lone pairs of electrons )?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!