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Ilya [14]
4 years ago
13

What is mostly commonly found element in the Earth's crust??​

Chemistry
2 answers:
topjm [15]4 years ago
8 0

Answer:

The most commonly found element in the earth's crust is Oxygen.

Explanation:

The<u> atomic umber of Oxygen is 8</u>.The <u>electronic configuration</u> of oxygen is <u><em>2,6</em></u>.It belongs to the <u>chalcogen </u>family in the periodic table.It is a strong oxidizing agent and highly reactive non-metal.The amount of oxygen present in the earth's crust is 46.6%.The oxygen exists in two forms ,they are O_{2(oxygen) and O_{3}(ozone).The major compound of it exists in the form of silicate minerals where it combines with other minerals.It also exists i the compound as carbonates and phosphates. Oxygen with acetylene is used to cut and weld the metals.In the medical field,Oxygen is used to ease the respiratory disease and it is also used to manufacture the the explosives.

MissTica4 years ago
3 0

Answer:

water/h20

Explanation:

the earth is mostly contained of water

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Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0
3 years ago
When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox
kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen  using Lead (IV) oxide as a catalyst.

  1. The catalyst surface area is directly proportional to the reaction rate
  • So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

     2. Also, Removing lead (IV) oxide from the reaction mixture  the reaction rate decreased because as the catalyst is removed.

     3.  Using 50 cm³ of hydrogen peroxide  doesn't affect the rate because the concentration of the reactant doesn't change.

     4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0
4 years ago
PLEASE HELP ME
ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

We were given the following:

Total pressure = 2.45 atm

Pressure of oxygen = 0.65 atm

Pressure of carbon monoxide = x

Pressure of carbon dioxide = 0.65 atm

Therefore:

2.45 = x + 0.65 + 0.65

2.45 = x + 1.3

x = 2.45 - 1.3

x = 1.15 atm

6 0
4 years ago
The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment of that molecule. A. True B
SOVA2 [1]

Answer:

The answer is True.

Explanation:

The sentence above is true it all adds up.

8 0
2 years ago
N is another unit for mass True or False
aliina [53]
N is newtons so it would be false
8 0
3 years ago
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