<u>Answer:</u> The moles of water produced are 1.54 moles.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of ethane = 15.42 g
Molar mass of ethane = 30.07 g/mol
Putting values in above equation, we get:

The chemical equation for the combustion of ethane follows:

By Stoichiometry of the reaction:
2 moles of ethane produces 6 moles of water
So, 0.513 moles of ethane will produce =
of water
Hence, the moles of water produced are 1.54 moles.
<span>a.the nearest 1 ml
1 mL is much more precise than 100 mL because 1 mL is a very small and precise unit of measurement</span>
Answer:
OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20
Explanation:
Butane burns is air (O2) according to the equation:
C4H10 + O2 —> CO2 + H20
Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;
There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:
C4H10 + O2 —> 4CO2 + H20
Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:
C4H10 + O2 —> 4CO2 + 5H20
Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2
as shown below
C4H10 + 13/2O2 —> 4CO2 + 5H20
Now we multiply through by 2 clear off the fraction and we obtained:
2C4H10 + 13O2 —> 8CO2 + 10H20
Answer:
The short steep ramp would be much harder because you will have to work more against gravity.
Explanation:
Answer:
5.85 gm.
Explanation:
We know that,
Normality =<u> Molarity × Molecular </u><u>weight</u>
Equivalent weight
Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5
Normality of NaCl= molarity=2
Now,
Normality= <u>weight</u><u> </u><u>in</u><u> </u><u>gram</u><u> </u><u>×</u><u>1000</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>
Volume ×equivalent weight
Weight in gram is given by,
<u>=</u><u>Normality × Volume × equivalent </u><u>weight</u>
1000
= <u>2× 50 × 58.</u><u>5</u>
1000
=5.85 gm.