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True [87]
3 years ago
6

Calcalculate potential energy given to a potato sack having a mass of 2 kg as I raise it to a height of 450 CM ​

Physics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

8.829 Joules

Explanation:

The potential energy of an object, is the energy it posses (the energy stored within the object) by virtue of its relative elevation or height, position, state, or arrangement

The potential energy of an object raised to a given height, P.E. = m·g·h

Where;

m = The mass of the object

g = The acceleration due to gravity, a constant ≈ 9.81 m/s²

h = The present height of the object

For the potato sack having a mass, m = 2 kg, and raised to a height, h = 450 cm = 0.45 m, we have;

The potential energy given to the potato sack, by raising its height, P.E. is given as follows;

P.E. = 2 kg × 9.81 m/s² × 0.45 m = 8.829 Joules

The potential energy given to the potato sack, P.E. = 8.829 Joules

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rosijanka [135]

Answer:

a

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b

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Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

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I tried looking at formulas, if you know the formula can you list it?
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y=mx+b

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