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3 years ago

Rewrite each fraction with a denominator of 24. 3/8 7/6

Mathematics

2 answers:

Illusion [34]3 years ago

6 0

9/24

28/24

If you need an explanation just ask

MakcuM [25]3 years ago

6 0

3/8 = 9/24
7/6 = 28/24

If we are trying to rewrite the fraction’s denominator we just multiply the current denominator to get it to 24. So 8x3 would equal 24. Then we just multiply the numerator by the same number. We used 3, so we do 3x3 which equals 9. Hence the first answer, 9/24.

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Find the equation of a line that is perpendicular to the line y=(1/3)x+4 and contains the point (-9,0)?

torisob [31]

Answer:

y = -3x - 27

Step-by-step explanation:

0 = -3[-9] + b

-27 = b

y = -3x - 27

* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES]:

⅓ → -3

I am joyous to assist you anytime.

7 0

3 years ago

1 calcule o valor das expressões A) 2x+(3.4)²+(7.7) B) 3x+(2.6)+(8.8)² C)7.6+(28.3)+(4)² D)7x-(7.8)+(9:3)

I am Lyosha [343]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given:

$A) \ \ 2x+(3.4)^2+(7.7) \\\\B) \ \ 3x+(2.6)+(8.8)^2\\\\C)\ \ 7.6+(28.3)+(4)^2 \\\\D)\ \ 7x-(7.8)+(9:3)$

For point A:

$\to 2x+(3.4)^2+(7.7)\\\\\to 2x+(11.56)+(7.7)\\\\\to 2x+19.26\\\\$

For point B:

$\to 3x+(2.6)+(8.8)^2\\\\\to 3x+(2.6)+77.44\\\\\to 3x+80.04$

For point C:

$\to \ 7.6+(28.3)+(4)^2 \\\\\to \ 7.6+(28.3)+16 \\\\\to \ 7.6+44.3 \\\\\to 51.9$

For point D:

$\to 7x-(7.8)+(9:3)\\\\\to 7x-(7.8)+ \frac{9}{3}\\\\\to 7x- \frac{23.4+9}{3}\\\\\to 7x- \frac{32.4}{3}\\\\\to 7x- 10.8$

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3 years ago

A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated

malfutka [58]

Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = ± √9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)

7 0

3 years ago

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storchak [24]

Answer:

x = 2

Step-by-step explanation:

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Daniel [21]

Answer:

perimeter of square

Step-by-step explanation:

5 0

3 years ago

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