When two systems in contact are not at the same temperature, ____

What is the radius of the 5th orbital in hydrogen?

iren2701 [21]

Answer:

So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.

Explanation:

pls mark me brainless hope this helps loves x!

6 0

2 years ago

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Question C) needs to be answered, please help (physics)

Zarrin [17]

(a) Differentiate the position vector to get the velocity vector:

r(t) = (3.00 m/s) t i - (4.00 m/s²) t² j + (2.00 m) k

v(t) = dr/dt = (3.00 m/s) i - (8.00 m/s²) t j

(b) The velocity at t = 2.00 s is

v (2.00 s) = (3.00 m/s) i - (16.0 m/s) j

(c) Compute the electron's position at t = 2.00 s:

r (2.00 s) = (6.00 m) i - (16.0 m) j + (2.00 m) k

The electron's distance from the origin at t = 2.00 is the magnitude of this vector:

||r (2.00 s)|| = √((6.00 m)² + (-16.0 m)² + (2.00 m)²) = 2 √74 m ≈ 17.2 m

(d) In the x-y plane, the velocity vector at t = 2.00 s makes an angle θ with the positive x-axis such that

tan(θ) = (-16.0 m/s) / (3.00 m/s) ==> θ ≈ -79.4º

or an angle of about 360º + θ ≈ 281º in the counter-clockwise direction.

3 0

3 years ago

28. In the diagram above which symbol represents the light bulb ?

Tanzania [10]

28. It's B
29. It's A

3 0

3 years ago

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What is hydraulic pressure?

Ilia_Sergeevich [38]

Hydraulic pressure is actually the pressure that is exerted to liquid and the pressure gets transmitted throughout the liquid. Since liquid cannot be compressed, so the pressure that was exerted on the liquid gets transmitted to the walls of the container containing the liquid. This theory is applied to the braking system of cars and some other vehicles. This is known as the hydraulic pressure. It is actually the science that is concerned with the laws of movements of a fluid and the application of this theory for engineering purpose. This theory has not only been used in cars but also in planes .

3 0

3 years ago

An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.

aivan3 [116]

Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

Mass of water = 258 g

Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

7 0

3 years ago

When two systems in contact are not at the same temperature, _____ occurs.