I’ve done this before the answer is B
Answer:
The magnitude of the applied torque is 
(e) is correct option.
Explanation:
Given that,
Mass of object = 3 kg
Radius of gyration = 0.2 m
Angular acceleration = 0.5 rad/s²
We need to calculate the applied torque
Using formula of torque

Here, I = mk²

Put the value into the formula



Hence, The magnitude of the applied torque is 
Answer:
10392.30N
Explanation:
We proceed by computing the individual force exerted by the boats
For the first boat
The angle is 30 degree to the vertical
Hence
Force = F cos θ
F=6000 cos 30
F=6000*0.866
F=5196.15 N
Since the boats are two and also at the same angle and also exerting the same force
The Net force = 2*5196.15
Net force=10392.30N
Power is the rate of work done given by dividing work done by time.Efficiency is the ratio of work output to work input
power input= 100 watts
power output = x
efficiency= 0.8
thus 0.8 = x/100, therefore x = 80
power is given by energy times time
hence time = 80/300000 = 0.00026 seconds
Time in hours = 0.00026/360 = 7.407 x 10 ∧7 hours