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valentinak56 [21]
3 years ago
11

Two technicians are discussing electronic leveling systems. Technician A says that a weight should be placed in the vehicle as p

art of the diagnostic procedure. Technician B says that many ride height sensors are adjustable. Which technician is correct?
A. Technician A only
B. Technician B only
C. Both A and B
D. Neither A nor B
Physics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

C. Both A and B

Explanation:

<em>Electronic leveling systems: </em>These are automatic lifting jacks use for raising  wheels and vehicle when parked or when work is to be done on the vehicle engine underneath or on wheels. unlike the manual jacks it is very quick and efficient.

Both technician right, for Technician A, a weight may be use during the procedure for balancing and leveling when raising, and for Technician B, the sensor in the electronic leveling systems is adjustable to adjust the height so as to maintain balancing and levelling.

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Describe how thermal energy is transferred​
ikadub [295]

Answer:

Thermal energy typically flows from a warmer material to a cooler material. Generally, when thermal energy is transferred to a material, the motion of its particles speeds up and its temperature increases. There are three methods of thermal energy transfer: conduction, convection, and radiation.

Explanation:

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4 0
3 years ago
8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer
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Answer:

the distance that the object is raised above its initial position is 5.625 m.​

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \  by \ the \ effort}{disatnce \ moved \  by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m

Therefore, the distance that the object is raised above its initial position is 5.625 m.​

3 0
3 years ago
A spherical shell of radius 9.0 cm carries a uniform surface charge density σ= 9.0 nC/m2. The electric field at r= 9.1 cm is app
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Answer:

995.12 N/C

Explanation:

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E = ( 9 x 10^9 x 9.156 x 10^-10) / (0.091 x 0.091)

E = 995.12 N/C

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Answer:

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Explanation:

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If this experiment is repeated at a place3 meters above the sea level the acceleration due to gravity is expected to
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