Answer:
r = 4.44 m
Explanation:
For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid
B = ρ g V
Now let's use Newton's equilibrium relationship
B - W = 0
B = W
The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)
σ = W / A
W = σ A
The area of a sphere is
A = 4π r²
W = W₁ + σ 4π r²
The volume of a sphere is
V = 4/3 π r³
Let's replace
ρ g 4/3 π r³ = W₁ + σ 4π r²
If we use the ideal gas equation
P V = n RT
P = ρ RT
ρ = P / RT
P / RT g 4/3 π r³ - σ 4 π r² = W₁
r² 4π (P/3RT r - σ) = W₁
Let's replace the values
r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000
r² (11.81 r -0.060) = 13000 / 4pi
r² (11.81 r - 0.060) = 1034.51
As the independent term is very small we can despise it, to find the solution
r = 4.44 m
If you only know its speed, that's not enough information to catch it. You could even chase it at DOUBLE that speed, and you'd never catch it if you were chasing in the wrong direction.
You also have to know the DIRECTION the runaway car is going, so that you can chase in the same direction.
Now that you know its speed AND direction, you know its velocity. You need that information to have any chance of catching it.
An isotonic solution is <span>a solution in which concentration or solute is equal to that of a cell placed in it. Thus, the system is in dynamic equilibrium, and so water molecules flow in both directions.
The correct answer is <u>C. w</u></span><span><u>ater molecules flow in both directions at the same rate.</u></span>
Answer:
Mercury is a metal that is used in
Mercury can be seen as an evening "star" near the sun's setting point or as a morning "star" near the sun's rising point. The evening star was given the name Hermes, and the morning star was given the name Apollo, since the ancient Greeks thought they were two separate things. Mercury, the Roman god's messenger, is the planet's name.
Answer:
1.15 rad/s²
Explanation:
given,
angular speed of turntable = 45 rpm
=
=
time, t = 4.10 s
initial angular speed = 0 rad/s
angular acceleration.
Hence, the angular acceleration of the turntable is 1.15 rad/s²
