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irga5000 [103]
3 years ago
6

A portable x-ray unit has a step-up transformer. The 120 V input is transformed to the 100 kV output needed by the x-ray tube. T

he primary has 50 loops and draws a current of 13.9 A when in use. What is the number of loops in the secondary
Physics
1 answer:
slega [8]3 years ago
3 0

Answer:

 N_s\approx41667 \hspace{3}lo ops

Explanation:

In an ideal transformer, the ratio of the voltages is proportional to the ratio of the number of turns of the windings. In this way:

\frac{V_p}{V_s} =\frac{N_p}{N_s} \\\\Where:\\\\V_p=Primary\hspace{3} Voltage\\V_s=V_p=Secondary\hspace{3} Voltage\\N_p=Number\hspace{3} of\hspace{3} Primary\hspace{3} Windings\\N_s=Number\hspace{3} of\hspace{3} Secondary\hspace{3} Windings

In this case:

V_p=120V\\V_s=100kV=100000V\\N_p=50

Therefore, using the previous equation and the data provided, let's solve for N_s :

N_s=\frac{N_p V_s}{V_p} =\frac{(50)(100000)}{120} =\frac{125000}{3} \approx41667\hspace{3}loo ps

Hence, the number of loops in the secondary is approximately 41667.

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1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t
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Answer:

F = 36 N

Explanation:

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Determine the final temperature of a gold nugget (mass = 376 g) that starts at 398 K and loses 4.85 kJ of heat to a snowbank whe
m_a_m_a [10]

Answer: Final temperature of a gold nugget will be 297 K

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

q=m\times c\times (T_{final}-T_{initial})

q = heat released  = -4.85 kJ = -4850 J

m = mass of metal =  376 g

T_{final} = final temperature of metal = ?

T_{initial} = initial temperature of metal = 398 K

c = specific heat of metal =

-4850=376\times 0.128\times (T_{final}-398)

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6 0
3 years ago
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