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jeka57 [31]
3 years ago
6

The real advantage to hydrostatic weighing is that it __________.

Physics
2 answers:
katovenus [111]3 years ago
7 0

The real advantage to hydrostatic weighing is that it gives one of the most accurate measurements of body fat.

KengaRu [80]3 years ago
7 0

Answer:

yup its B as in bagel

Explanation:

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A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially
Alchen [17]

The new speed of car is 10.9 m/s

<h3 />

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

Learn more about momentum here:

brainly.com/question/22257327

#SPJ1

5 0
2 years ago
Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod
aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force=\frac{Gm_{1}m_{2} }{r^{2}}

Coulombs's Law= \frac{Kq_{1}q_{2} }{r^{2}}

6 0
4 years ago
Read 2 more answers
One of the element carbon combines with one of the element oxygen to form one of the compound carbon dioxide.
saul85 [17]
False. C + O --> CO not CO2. Carbonmonoxide
3 0
3 years ago
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Now, look at a general function f(x), as shown in (Figure 4) .
Nataliya [291]
We can't look at Figure 4. We don't know where a and b are. We can't see the blue shaded area. We don't know what our method above was. We can't see the green skinny rectangle.
7 0
3 years ago
Name the two ends of a magnet
astra-53 [7]
The positive and the negative side
I hope this helps :)
6 0
3 years ago
Read 2 more answers
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