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3 years ago

The real advantage to hydrostatic weighing is that it __________.

Physics

2 answers:

katovenus [111]3 years ago

7 0

The real advantage to hydrostatic weighing is that it gives one of the most accurate measurements of body fat.

KengaRu [80]3 years ago

7 0

Answer:

yup its B as in bagel

Explanation:

You might be interested in

Most interstellar clouds are: Most interstellar clouds are: much bigger than our solar system. similar in size to clouds in Eart

cupoosta [38]

Answer:

Most interstellar clouds are much bigger than our solar system.

Explanation:

An interstellar cloud refers:

It is generally an accumulation of gas, plasma, and dust in our and other galaxies.
It is basically a denser-than-average region of the interstellar medium (ISM).

Interstellar clouds can be large up to 106 solar masses

It is also often said to be the most massive entities in the galaxy.

Hence

we can say about Interstellar clouds,

They are much bigger than our solar system.

learn more about interstellar clouds here:

<u>brainly.com/question/14726563</u>

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#SPJ4

4 0

2 years ago

A 66-kg diver jumps off a 9.7-m tower. (a) Find the diver's velocity when he hits the water. (b) The diver comes to a stop 2.0 m

Mariana [72]

Answer:

(a) 13.795 m/s.

(b) -3140.28 N.

Explanation:

(a) Using newton's equation of motion,

v² = u² + 2gs.......................... Equation 1

Where v = final velocity, u = initial velocity, s = height of the tower, g = acceleration due to gravity.

Given: s = 9.7 m, u = 0 m/s ( jump from a height), g = 9.81 m/s².

Substitute into equation 1

v² = 0² + 2×9.81×9.7

v² = 190.314

v = √(190.314)

v = 13.795 m/s.

Hence the velocity of the driver when he hits the water = 13.795 m/s.

(b)

F = ma.................... Equation 2

Where F = force exerted on the diver, m = mass of the diver, a = acceleration of the diver below the water surface.

Also using

v² = u² + 2as ............ Equation 3

Note: At the point when the diver enters the water, u = 13.795 m/s, and at the point when the diver comes to a complete stop, v = 0 m/s

Given: s = 2.0 m, u = 13.795 m/s, v = 0 m/s

Substitute into equation 3

0² = 13.795²+2(2a)

0 = 190.30203 + 4a

-4a = 190.30203

a = 190.30203/-4

a = -47.58 m/s²

Also given: m = 66 kg,

Substitute into equation 3

F = (-47.58)(66)

F = -3140.28

Note: The Force is negative because it act against the motion of the diver.

Hence the net force exerted on the diver while in the water = -3140.28 N.

7 0

3 years ago

A machine gun fires 50-g bullets at the rate of 4 bullets per second. The bullets leave the gun at a speed of 1000 m/s. What is

TEA [102]

Answer:

Average recoil force experienced by machine will be 200 N

Explanation:

We have give mass of each bullet m = 50 gram = 0.05 kg

There are 4 bullets

So mass of 4 bullets = 4×0.05 = 0.2 kg

Initial speed of the bullet u = 0 m/sec

And final speed of the bullet v = 1000 m/sec

So change in momentum $P=m(v-u)=0.2\times (1000-0)=200kgm/sec$

Time is given per second so t = 1 sec

We know that force is equal to rate of change of momentum

So force will be equal to $F=\frac{200}{1}=200N$

So average recoil force experienced by machine will be 200 N

5 0

3 years ago

If 2 objects had the same momentum, what must be true about the mass of the object that traveled the fastest?

julsineya [31]

Yes, the above-given statement is true

<u>Explanation:</u>

The product of the mass x the velocity will be the same for both. Momentum is the action of a body with a particular mass through space and there is the conservation of momentum.
Momentum is described as the mass of the object multiplied by its velocity.
<u>Momentum (p) = Mass (M) * Velocity (v)</u>
Therefore for two objects with many masses to have a similar momentum, then the lighter one has to be moving quicker than the heavier object.

4 0

2 years ago

Help with question 16 and 17

storchak [24]

Your answer is correct.

___

The fractional change in resistance is equal to the given temperature coefficient multiplied by the change in temperature.

R = R₀×(1 + α×ΔT)

R = (10.0 Ω)×(1 + 0.004×(65 -20)) = 11.8 Ω

5 0

3 years ago