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Katena32 [7]
3 years ago
8

If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

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The five types of states of matter are solid, liquid, gas, plasma and Bose-Einstein condensate.

Solid objects do not move a lot relative to themselves. Their molecules stay stacked neatly with no intermolecular spaces. They do not have much energy, or heat hence the molecules in solid state don't show movement.

Liquid state have more heat and more energy and a little more intermolecular space than solid. Their molecules are no longer stacked neatly due to presence of air capsules, but they still touch each other. Their structure is uncertain and can flow, their shape will alter quickly and dramatically with outside forces, but they will essentially remain a single mass unless pushed apart.

Gasses have even more energy than liquid and solid. Due to presence of high intermolecular spaces they flow like liquids, but are even more susceptible to the forces acting on them. Their molecules don’t touch each other, but are still close enough to bounce into one another frequently.

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8 0
1 year ago
PH & POH
Mashcka [7]

Answer:

<h2>4.0 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H}^{+}]

From the question we have

ph =  -  log(9.25 \times  {10}^{ - 5} )  \\  = 4.03385

We have the final answer as

<h3>4.0</h3>

Hope this helps you

5 0
3 years ago
a 1.25g sample of ore containing iron pyrite (FeS2) was pulverized and ignited in air, converting the FeS2 to Fe2O3 and SO2(g).
svp [43]

Answer:

28.9%

Explanation:

Let's consider the following balanced equation.

2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂

We can establish the following relations:

  • The molar mass of Fe₂O₃ is 159.6 g/mol
  • 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
  • 1 mole of Fe is in 1 mole of FeS₂
  • The molar mass of Fe is 55.84 g/mol

The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:

0.516gFe_{2}O_{3}.\frac{1molFe_{2}O_{3}}{159.6gFe_{2}O_{3}} .\frac{2molFeS_{2}}{1molFe_{2}O_{3}} .\frac{1molFe}{1molFeS_{2}} .\frac{55.84gFe}{1molFe} =0.361gFe

The percent of Fe in 1.25 g of the ore is:

\frac{0.361g}{1.25g} .100\%=28.9\%

4 0
3 years ago
What is the pH of a solution that has a pOH of 5.9
Stella [2.4K]

Answer:

pH = 8.1

Explanation:

Assuming that we are at 25 degrees Celsius, pH + pOH = 14.

We can then plug in the given pOH and solve for pH:

pH + pOH = 14

pH + 5.9 = 14

pH = 14 - 5.9 = 8.1

7 0
3 years ago
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