3 years ago

What is the mass of 4.49 x 10º carbon dioxide, CO2, molecules?

1 answer:

3 0

To find this you have to find the molar mass of CO2 which you can get on the periodic table, 12 + 16 + 16 = 44 g/mol

4.49 x 10^0 / 44 g/mol = .1020 mol CO2

1 mol = 6.022 x 10^23 molecules (avogadros number)

so .1020 mol x 6.022 x 10^23 =
6.14 x 10 ^22 molecules CO2

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How many grams of Na2CO3 are present in 11.8 mL of a solution that is 22.0% Na2CO3 by mass? The density of the solution is 1.10

Sergeeva-Olga [200]

Answer:

The Answer is 2,86 grs Na2CO3

Explanation:

What we have to do is find the mass of Na2CO3 as a pure component or solute. That's because the 11,8 mL are a solution of Na2CO3. This means, the sum between the solute Na2CO3 and water. To find the grams of Na2CO3 as pure component we create a factor series as is shown in the attached file.

Data:

Density of solution (ρ) = 1,10 grs sln Na2CO3/mL sln Na2CO3

Mass Percentage (%) = 22 grs Na2CO3/100 grs sln Na2CO3

The procedure is explained in the attached file