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Lena [83]
3 years ago
11

What is the mass of 4.49 x 10º carbon dioxide, CO2, molecules?

Chemistry
1 answer:
Maslowich3 years ago
3 0
To find this you have to find the molar mass of CO2 which you can get on the periodic table, 12 + 16 + 16 = 44 g/mol

4.49 x 10^0 / 44 g/mol = .1020 mol CO2

1 mol = 6.022 x 10^23 molecules (avogadros number)

so .1020 mol x 6.022 x 10^23 =
6.14 x 10 ^22 molecules CO2
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Which of these is not a characteristic of a renewable resource? Question 1 options: Used up faster than they are able to be repl
klemol [59]

Answer:

can be replaced in a short amount of time

Explanation:

done

7 0
3 years ago
What is the pH of a solution with a concentration of 5.2 × 10–8 M H3O+?
lora16 [44]

Answer : The pH of a solution is, 7.28

Solution : Given,

Concentration of hydronium ion, H_3O^+ = 5.2\times 10^{-8}M

pH : It is defined as the negative logarithm of hydronium ion concentration or hydrogen ion concentration.

pH=-\log [H_3O^+]

Now put the value of hydronium ion concentration in this expression, we get the pH of the solution.

pH=-\log (5.2\times 10^{-8})=7.28

Therefore, the pH of a solution is, 7.28

7 0
3 years ago
If the OH‑ ion concentration in an aqueous solution at 25.0 °C is 6.6 x 10‑4 M, what is the molarity of the H+ ion?
Tresset [83]

Answer:

1.5 × 10⁻¹¹ M

Explanation:

Step 1: Given data

  • Concentration of OH⁻ ([OH⁻]): 6.6 × 10⁻⁴ M
  • Temperature: 25°C
  • Concentration of H⁺ ([H⁺]): ?

Step 2: Consider the self-ionization of water

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Step 3: Calculate the molar concentration of H⁺

We will use the equilibrium constant for the self-ionization of water (Kw).

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴

[H⁺] = 1.5 × 10⁻¹¹ M

6 0
4 years ago
Which of the following best describes what happens when hydrogen and oxygen to form water?
Sever21 [200]

Atoms are combining to form molecules

6 0
3 years ago
An archaeologist finds 14C in a sample of material to be decaying at 20 Geiger Counter clicks per second. A modern equivalent sa
Kay [80]

Answer:

17188 years

Explanation:

Recall the formula;

0.693/t1/2 = 2.303/t log(No/N)

t1/2 = half life of 14C

No = initial activity of 14C

N = activity of 14C at time t

t = age of the sample

Substituting values

0.693/5730= 2.303/t log(160/ 20)

1.21 * 10^-4= 2.0798/t

t = 2.0798/1.21 * 10^-4

t = 17188 years

4 0
3 years ago
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