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3 years ago

What is the mass of 4.49 x 10º carbon dioxide, CO2, molecules?

1 answer:

3 0

To find this you have to find the molar mass of CO2 which you can get on the periodic table, 12 + 16 + 16 = 44 g/mol

4.49 x 10^0 / 44 g/mol = .1020 mol CO2

1 mol = 6.022 x 10^23 molecules (avogadros number)

so .1020 mol x 6.022 x 10^23 =
6.14 x 10 ^22 molecules CO2

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What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid?.

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Answer:

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.

Explanation:

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2 years ago

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Answer:

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3 years ago

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4 years ago

Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2

Flauer [41]

Answer:

$\boxed{28.81}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 58.12 44.01

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m/g: 9.511

1. Moles of C₄H₁₀

$\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}$

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

$\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}$

3. Mass of CO₂

$\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}$

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3 years ago

C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)<br><br> Which type of reaction is this?

erastova [34]

Answer: Combustion

Explanation:

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1 year ago