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vitfil [10]
3 years ago
14

Assume that the pictured magnet is being moved into the solenoid. If the polarity of the magnet is reversed and then moved into

the solenoid, what happens?
Physics
1 answer:
dangina [55]3 years ago
4 0

Answer:

The direction of the induced emf is revered, and hence the direction of the induced current.

Explanation:

When the polarity of the magnet is revered, the direction of the magnetic field is also reversed, and therefore, according to Faraday's law

\varepsilon = NA\dfrac{dBcos(\theta)}{dt}

\varepsilon = -NA\dfrac{dBcos(\theta)}{dt}

since the magnetic field changes sign from B to -B.

Hence, the effect is that the direction of the emf induced is reversed, which also reverses the direction of the induced current in the solenoid.

P.S:<em> The cause of confusion here is the direction of magnetic field lines from the magnetic</em>, and so you must remember that <em>field lines begin at the north pole and end at the south pole.</em>

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The fulcrum is the
olga_2 [115]

Answer:

point of support on which a lever rotates.

Explanation:

The fulcrum is the point of support on which a lever rotates. Fulcrum is a pivotal part of simple machines.

The fulcrum provides the platform for a lever to torque.

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6 0
3 years ago
suppose a ball is thrown vertically upward. Eight seconds later it returns to its point of release. What is the initial velocity
valentinak56 [21]
The ball took half of the total time ... 4 seconds ... to reach its highest
point, where it began to fall back down to the point of release.

At its highest point, its velocity changed from upward to downward. 
At that instant, its velocity was zero.

The acceleration of gravity is 9.8 m/s².  That means that an object that's
acted on only by gravity gains 9.8 m/s of downward speed every second. 

-- If the object is falling downward, it moves 9.8 m/s faster every second.

-- If the object is tossed upward, it moves 9.8 m/s slower every second.

The ball took 4 seconds to lose all of its upward speed.  So it must have
been thrown upward at  (4 x 9.8 m/s)  =  39.2 m/s .

(That's about  87.7 mph straight up.  Somebody had an amazing pitching arm.)
6 0
3 years ago
Vector A has magnitude of 15.0 m/s and is 75° counter-clockwise up from the x-axis. What are the x- and y-components of the vect
LiRa [457]

Answer:

x component 3.88 y- component 14.488

Explanation:

We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure

Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )

y- component will be 15 sin 75°=14.488

For verification the resultant of x and y component should be equal to 15

So resultant =\sqrt{14.488^2+3.88^2}=15

3 0
3 years ago
What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?
sveta [45]
Momentum = (mv). 
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>
8 0
3 years ago
An airplane with an airspeed of 120 km/h has a heading of 30 degree east of North in a wind that is blowing toward the east at 6
lesya692 [45]

Answer:

Explanation:

Velocity of plane relative to ground V_pg = ?

Given the velocity in vector form ,

velocity of plane relative to air V_pw = 120 cos30 i + 120sin30j

V_wg = 60 i

V_pg = V_pw +V_wg

= 120 cos30 i + 120sin30j + 60i

= 164 i + 60 j

magnitude

=251 km / h

=

8 0
3 years ago
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