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just olya [345]
3 years ago
8

A soccer player kicks a ball horizontally off a 40.0-m-high cliff into a pool of water. If the player hears the sound of the spl

ash 3.00 s later, what was the initial speed given to the rock? Assume the speed of sound in air is 343 m/s. Determine the speed of the ball immediately before it reaches the pool of water.
Physics
1 answer:
JulijaS [17]3 years ago
8 0

the speed of the ball before it reaches the pool of water would be 9.91 m/s.

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An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m
Svetllana [295]

The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

<h3>Work done by the force experienced  by the object</h3>

The magnitude of the work done by force experience by the object is calculated as follows;

W = f.d

where;

  • F is the applied force (2xyi + 3yj), where x and y are in meters
  • d is the displacement of the object = (a, b)

The work done by the force is determined from the dot product of the force and the displacement of the object.

F = (2xyi + 3yj).(a + b)

W = (2abi + 3bj).(ai + bj)

W = (2a²b + 3b²)J

Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

The complete question is below:

The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.

How much work does the force do?

Learn more about work done here: brainly.com/question/8119756

5 0
3 years ago
Which of the following is NOT a function of the skeletal system?
puteri [66]
D
Hope this helps
And
4 0
3 years ago
Read 2 more answers
1. Una bola de 0.510 kg de masa se mueve al este (dirección +x) con una rapidez de 4.80 m/s y choca frontalmente con una bola de
Grace [21]

Responder:

3,37 m / s, + ve x - dirección

Explicación:

Utilizando la ley de conservación de la cantidad de movimiento expresada por la fórmula;

m1u1 + m2u2 = (m1 + m2) v

m1 y m2 son las masas de los objetos

u1 y u2 son sus velocidades iniciales

v es su velocidad común

Dado

m1 = 0,519 kg

u1 = 4,80 m / s

m2 = 0,220 kg

u2 = 0 m / s (cuerpo en reposo)

Necesario

Velocidad común v

Sustituir en la fórmula los valores dados;

0,519 (4,8) + 0,22 (0) = (0,519 + 0,220) v

2,4912 + 0 = 0,739 v

2,4912 = 0,739v

Dividir ambos lados por 0,739

2,4912 / 0,739 = 0,739 / 0,739

<em>v = 3,37 m / s </em>

<em>Por lo tanto, la rapidez de ambas bolas después de la colisión es de 3.37 m.s hacia la dirección x positiva, ya que m1> m2 y la velocidad común es positiva.</em>

6 0
3 years ago
The diagram shows a stone suspended under the surface of a liquid from a string. The stone experiences a pressure caused by the
Ivan
Where is the diagram? What is the question?
6 0
3 years ago
A particle with charge 3.20×10−19 c is placed on the x axis in a region where the electric potential due to other charges increa
lys-0071 [83]

Answer:

-5 V

Explanation:

The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

vb−va

is negative.

We can calculate the potential difference between the two points by using the law of conservation of energy:

\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0

where:

\Delta K=+1.6\cdot 10^{-18} J is the change in kinetic energy of the particle

q=3.2\cdot 10^{-19} C is the charge of the particle

\Delta V =V_b-V_a is the potential difference

Re-arranging the equation, we can find the value of the potential difference:

\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V

8 0
3 years ago
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