A young boy of mass m = 25 kg sits on a coiled spring that has been compressed to a length 0.4 m shorter than its uncompressed l
ength and then held at this length. Suddenly the spring is released, and the boy flies vertically into the air. He reaches a maximum distance 0.5 m above his initial position. The spring is ideal and massless and we ignore the air friction. What is the spring constant k of the spring?
What is the speed of the boy when he is 0.4 meters above his starting position?
The spring's elastic potential energy is converted into elastic potential energy of the boy. Potential energy = elastic energy mgh = 1/2 kx² k = (2 * 25 * 9.81 * 0.5) / 0.4² k = 1533 N/m
We will apply 2as = v² - u², with u = 0 a = F/m F = kx a = kx/m
I think it's how far out the water goes from the beach before the tsunami because before tsunami usually the water goes back way behind the tide before tsunami and that tells them everything they need I think
