A young boy of mass m = 25 kg sits on a coiled spring that has been compressed to a length 0.4 m shorter than its uncompressed l
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Answer:
Explanation:
Given that:
Charge (q) on the particle = 3 × 10⁻⁸ C
mass (m) of the particle = 6 × 10⁻⁹ kg
at a distance x = 15 cm , the velocity in the plate = 900 m/s²
For the square plate, the surface charged density σ = -8 × 10⁻⁶ C/m²
To start with calculating the electric field as a result of the square plate; we use the formula;
On the square plate; The electric force F = Eq
The acceleration
For the particle, the velocity at distance x = 7 m can be calculated by using the formula:
From the calculation, we realize that the charge acting between the particle and the plate is said to be "opposite".
Hence, the force is an attractive force.
Similarly, there is a gradual increase exhibited by the velocity of the particle.
Therefore, the particles get to the detector, but the detector failed to get detect due to the velocity which is greater than 1000 m/s.
(a) The ball has a final velocity vector
with horizontal and vertical components, respectively,
The horizontal component of the ball's velocity is constant throughout its trajectory, so , and the horizontal distance <em>x</em> that it covers after time <em>t</em> is
It lands 103 m away from where it's hit, so we can determine the time it it spends in the air:
The vertical component of the ball's velocity at time <em>t</em> is
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for the vertical component of the initial velocity:
So, the initial velocity vector is
which carries an initial speed of
and direction <em>θ</em> such that
(b) I assume you're supposed to find the height of the ball when it lands in the seats. The ball's height <em>y</em> at time <em>t</em> is
so that when it lands in the seats at <em>t</em> ≈ 6.38 s, it has a height of
The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.
Therefore the magnitude of the butterfly's displacement is 9m
