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Doss [256]
3 years ago
10

Question 3 (1 point) The extinction coefficient for copper sulfate in aqueous solution is 12 M-1.cm-1 at 800 nm. If the absorban

ce of the copper sulfate solution in 0.50 cm cuvette is 0.50 at 800 nm, the concentration of copper sulfate in this solution is: O3M O 83 mm 8.3 mm 12 M-cm 0.042 M
Chemistry
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

The concentration of the copper sulfate solution is 83 mM.

Explanation:

The absorbance of a copper sulfate solution can be calculated using Beer-Lambert Law:

A = ε . c . <em>l</em>

where

ε is the extinction coefficient of copper sulfate (ε = 12 M⁻¹.cm⁻¹)

c is its molar concentration (what we are looking for)

l is the pathlength (0.50 cm)

We can use this expression to find the molarity of this solution:

c=\frac{A}{\epsilon.l } =\frac{0.5}{12M^{-1}cm^{-1}0.50cm  } =0.083M=83mM

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Direct electron transfer from a singlet reduced species to a triplet oxidizing species is quantum-mechanically forbidden
posledela

Direct electron transfer from a a singlet reduced species to a triplet oxidizing species is quantum-mechanically forbidden.

<h3><u>Transfer from singlet to triplet:</u></h3>
  • Either an excited singlet state or an excited triplet state will occur when an electron in a molecule with a singlet ground state is stimulated (through radiation absorption) to a higher energy level.
  • All electron spins in a molecule electronic state known as a singlet are coupled.
  • In other words, the ground state electron and the stimulated electron's spin are still coupled (a pair of electrons in the same energy level must have opposite spins, per the Pauli exclusion principle).
  • The excited electron and ground state electron are parallel in a triplet state because they are no longer coupled (same spin).
  • It is less likely that a triplet state would arise when the molecule absorbs radiation since excitation to a triplet state necessitates an additional "forbidden" spin transfer.

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8 0
2 years ago
The prefix 'kilo-' means a thousand. So a kilo-gram is a thousand grams. 1 kilogram=1,000 grams How many kilograms is 1,008 gram
lesantik [10]

<u>Answer:</u>  1.0 kilograms.

<u>Explanation:</u>

One kilogram is equal to a thousand grams.

Supposing x to be the number of kilograms equal to one thousand and eight grams, we can write it as:

1 kg = 1000 grams

x kg = 1008 grams

To solve for x, we can simply divide 1008 grams by 1000 thousand grams to get the answer.

x = 1008 / 1000

x = 1.008

Rounding this value to the nearest tenth, it will become 1.0 kilograms.

4 0
3 years ago
Uranium in the isotope below had 140 nutrons​
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Answer:

It has 140 neutrons because Mass number= No of protons + no of neutrons

4 0
3 years ago
Be sure to answer all parts.
Liula [17]

A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²

B. The cost of the patch to the nearest cent is 734 cents

<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>

We can convert 16.1 cm² to km² as illustrated below:

Conversion scale

1 cm² = 1×10⁻¹⁰ km²

Therefore,

16.1 cm² = 16.1 × 1×10⁻¹⁰

16.1 cm² = 1.61×10⁻⁹ km²

Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²

<h3>B. How to determine the cost in cent</h3>

We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:

1 cm² = 0.155 in²

Therefore,

16.1 cm² = 16.1 × 0.155

16.1 cm² = 2.4955 in²

Finally, we shall the determine the cost in centas fo r llow:

  • Cost per in² = $2.94 = 294 cent
  • Cost of 2.4955 in² =?

1 in² = 294 cent

Therefore,

2.4955 in² = 2.4955 × 294

2.4955 in² = 734 cents

Thus, the cost of the patch is 734 cents

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6 0
1 year ago
4. How does the kinetic theory of gases explain the weather changes happening in the troposphere? You can also research on the I
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According to the kmt pressure is directly proportional to the number of collision between particles
4 0
3 years ago
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