Answer:
The height of the image is, h' = 6.0 cm
The image is erect.
Explanation:
Given data,
The object distance, u = -5 cm
The focal length of convex lens, f = 10 cm
The object height, h = 3 cm
The lens formula,



v = -10 cm
The magnification factor of lens

m = 2



h' = 6 cm
The height of the image is, h' = 6 cm
The image is erect.
Explanation:
Let us assume that the mass of a pitched ball is 0.145 kg.
Initial velocity of the pitched ball, u = 47.5 m/s
Final speed of the ball, v = -51.5 m/s (in opposite direction)
We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.
Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

Hence, this is the required solution.
Answer:
1.931 kilometres is the answer of 1.2 miles
Fundamental frequency is the "base frequency" upon which the sound is built.
It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place.