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Leviafan [203]
3 years ago
13

What volume of a 9.00 M NaOH stock solution would you need to make 800. ML of a 0.750 M NaOH solution

Chemistry
1 answer:
joja [24]3 years ago
8 0

Answer: 66.66 ml

Explanation: Using Molarity equation:

M_1V_1 (stock solution)=M_2V_2(solution to be prepared)

given: M_2=0.750M

V_2=800ml

M_1=9.00M

V_1=?

9.00M\times V_1 (stock solution)=0.750M\times 800ml (solution)

V_1= 66.66ml

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Atoms of which of the following elements have the smallest atomic radius?
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Answer:

The answer is helium, I hope this is helpful :)

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2 years ago
The radioisotope radon-222 has a half life of 3.8 days. How much of a 10 gram sample of radon-222 would be left after 15.2 days?
djyliett [7]

Answer:

0.625 g

Explanation:

Given data:

Half life of radon-222 = 3.8 days

Total mass of sample = 10 g

Mass left after 15.2 days = ?

Solution:

Number of half lives = T elapsed / Half life

Number of half lives = 15.2 / 3.8

Number of half lives = 4

At time zero = 10 g

At first half life = 10 g/2 = 5 g

At 2nd half life = 5 g/ 2= 2.5 g

At third half life = 2.5 g/2 = 1.25 g

At 4th half life = 1.25 g/2 = 0.625 g

4 0
2 years ago
How many grams of NaCl are needed to make 0.800 liter of a 5.00 M solution?
ziro4ka [17]

Answer:

             0.324 g is required to make 5.00 M solution of NaCl in 0.800 L.

Given data:

                 Molarity = 5.00 M

                 Formula Mass = 58.5 g/mol

                 Required volume = 0.800 L

To Find;

               Mass in gram = ?

Solution:

              Formula for calculating mass in gram is given as,

              Mass in gram = Molarity × Formula mass × Volume required / 1000 putting values

              Mass in gram = 5.00 M × 58.5 g/mol × 0.800 L / 1000

               Mass in gram = 0.234 g


6 0
3 years ago
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Answer:

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Explanation:

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