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babunello [35]
4 years ago
15

The instruments attached to a weather balloon have a mass of 5 kg. The balloon is released and exerts an upward force of 106 N o

n the instruments. The acceleration of gravity is 9.8 m/s 2 . What is the acceleration of the balloon and the instruments? Answer in units of m/s 2
Physics
2 answers:
MrMuchimi4 years ago
8 0

Answer:

Acceleration, a=11.4\ m/s^2

Explanation:

It is given that,

Mass of the balloon, m = 5 kg

Upward force acting on it, F = 106 N

Acceleration due to gravity, a=9.8\ m/s^2

As the accelerating upward, the net force acting on it is given by :

F_{net}=F-mg

ma=F-mg

a is the acceleration of the balloon and the instruments

a=\dfrac{F-mg}{m}

a=\dfrac{106-5\times 9.8}{5}

a=11.4\ m/s^2

So, the acceleration of the balloon and the instrument is 11.4\ m/s^2. Hence, this is the required solution.

Illusion [34]4 years ago
6 0

Answer:

acceleration of the balloon is 11.4 m/s²

and

The instruments accelerate downwards at 9.8 m/s²

Explanation:

given data

mass = 5 kg

force = 106 N

acceleration of gravity = 9.8 m/s²

to find out

the acceleration of the balloon and the instruments

solution

we find weight of the instruments that is

weight W = mg

here m is mass and g is acceleration of gravity

W = 5 ×9.8

weight W = 49 N

and

so net upward force on the instruments is

net upward force F = 106 - 49

net upward force F = 57 N

and

The acceleration of the balloon is

Force = ma

57 = 5 a

a = 11.4 m/s²

acceleration of the balloon is 11.4 m/s²

and

The instruments accelerate downwards at 9.8 m/s²

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The static friction force is
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Answer:

The answer is the third option, the minimum force required to overcome static friction and move an object.

Explanation:

The first choice is talking about an object moving, and anything moving relates to <em>kinetic </em>friction, not static friction. I don't think it's the fourth option because, even with the net force being 0, the object could still be moving (again relating to kinetic friction).

3 0
4 years ago
Se colocan tres objetos, muy cerca uno del otro, dos al mismo tiempo. Cuando se juntan los objetos A y B, se repelen. Cuando se
docker41 [41]

Answer:

Los objetos A y C tienen cargas del mismo signo (opcion a)

Explanation:

Hay dos tipos de cargas : cargas positivas y cargas negativas.

La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:

  • La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva).
  • El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).

Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.

Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.

Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.

Por lo que podes concluir que <u><em>los objetos A y C tienen cargas del mismo signo (opcion a)</em></u>

8 0
3 years ago
A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise. 1. Wha
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1. What is the skydiver's acceleration?

Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.
3 0
3 years ago
Read 2 more answers
On flat ground, a 70-kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the
Darina [25.2K]

Answer:

C 350W

Explanation:

Given power output to walk on a flat ground to be 300W, h = 0.05x, v = 1.4m/s

m = 70kg and g =9.8m/s².

x = horizontal distance covered

Total energy used = potential energy used in climbing and the energy used in a walking the horizontal distance.

E = mgh + 300t

Where t is the time taken to cover the distance

x = vt and h = 0.05vt

So

E = mg×0.05×vt + 300t

Substituting respective values

E = 70×9.8×0.05×1.4t +300t = 348t

P = E/t = 348W ≈ 350W.

4 0
4 years ago
The diver on the diving board is 10 meters high and has a mass of 0.050kg, what is his GPE?
sveta [45]

Answer:

<h2>4.9 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 0.05

We have the final answer as

<h3>4.9 J</h3>

Hope this helps you

6 0
3 years ago
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