Question

If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be

Answer 1

Well, the "  kg-m/s² " is a Newton ... that's a [force].

When it's multiplied by another 'm', you get  " kg-m²/s² ".
That's [force] · [distance], which is [work] or [energy].

So far, we have  [energy] / C .

If the 'C' stands for 'Coulomb' of charge, then the whole thing
is [energy] / [charge] or " joule / Coulomb ".  That's a volt !

So the whole thing is a unit of electrical potential, potential difference,
or electromotive force.

When I first saw this question, I was trying hard to make it a unit
of something that has to do with heat, because I thought that big
' C ' out at the end was actually ' °C ' for Celsius degree.  But I think
the electrical stuff is better.  So that's my answer and I'm stickin' to it. 

Answer 2

It would be Joules.
Workdone is measured in Joules.
Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
          = kgms⁻²

Distance = m

So, Force * distance
       kgms⁻² * m

Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
m¹ * m¹ = m¹⁺¹ = m²
s⁻² is also = s / 2