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Umnica [9.8K]
4 years ago
13

8. A 10kg bowling ball would require what force to accelerate down the

Physics
1 answer:
bogdanovich [222]4 years ago
4 0

Answer:

Given a mass of 10kg and an acceleration of 3ms2 , we can calculate the net force on the bowling ball from the above equation. Therefore, 30N of force is required to accelerate the bowling ball down the alleyway at a rate of 3ms2 .

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Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a
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Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

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3 years ago
A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall
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Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

W_P=Px

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

W_P=(171N)(8.80m)=1504.8J

(b) The work don by the friction force is:

W_f=F_fx=\mu N x=\mu Mg x

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J

(c) The Normal force is

N=Mg=(46.0kg)(9,8m/s^2)=450.8N

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

W_N=0J

(d) the same as before:

W_g=0J

8 0
3 years ago
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Answer:

well... when the horse stops/rests, or if it is blocked by a surface or anything of solid background.

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3 0
4 years ago
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adoni [48]

Answer:

thanks

Explanation:

5 0
3 years ago
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