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FinnZ [79.3K]
3 years ago
8

A spring with a mass attached is initially at rest. It is then stretched 2 cm by a physics student. Another physics student with

a similar mass and spring system then stretches their spring to 4 cm. Compare and contrast the potential energies of the springs after they are stretched by the students. *
Physics
1 answer:
Andrew [12]3 years ago
3 0
The student who displaced the spring by 2 cm has less potential energy than the student who displaced the spring by 4 cm, this is because potential energy (elastic) is directly proportionate to extension (displaced amount), so as the amount of displacement of the spring is higher, then the potential energy of the springs is higher and vice versa.
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A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
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<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

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t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
3 years ago
1. A metal ball has a mass of 20 g and a volume of 6 cm3.Find its density
vesna_86 [32]

Answer:

density of the ball is 3.33 g/cc

Explanation:

As we know that the density is the ratio of mass and volume

here we know that

mass = 20 g

volume = 6 cubic cm

so we will have

\rho = \frac{m}{V}

\rho = \frac{20}{6} g/cm^3

\rho = 3.33 g/cm^3

4 0
3 years ago
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