Answer:
lift force = 0.213 N
Drag force =
Explanation:
Given: velocity v = 10 m/s
w = 100 rev/sec
diameter d = 3cm
density D = 1.2kg/m3
lift force =
Substituting the values into the equation, we obtain
lift force = 0.213 N
Drag force = C*D*A*v/2
where C = 0.5
substituting the values into the equation again, we have
Drag force =
Explanation:
Given that,
The mass of rock, m = 2.35-kg
It was released from rest at a height of 21.4 m.
(a) The kinetic energy is given by :
As the rock was at rest initially, it means, its kinetic energy is equal to 0.
(b) The gravitational potential energy is given by :
It can be calculated as :
(c) The mechanical energy is equal to the sum of kinetic and potential energy such that,
M = 0 J + 492.84 J
M = 492.84 J
Hence, this is the required solution.