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ICE Princess25 [194]
3 years ago
11

I need help on this math problem?!

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Hello from MrBillDoesMath!

Answer:

This is the second choice from the top  ( - 5.81)


Discussion:

The five terms are:

-3 - 3/2 - 3/4 -3/8 - 3/16 =

-3 ( 1 + 1/2 + 1/4 + 1/8 + 1/16) =

-3 (31/16) =

-93/16 =

-5 13/16 =

- 5.8125  ( approximately)


This is the second choice from the top

Thank you,

MrB

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On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
Select the correct answer from each drop-down menu.
Nesterboy [21]

Answer:

negative

positive

Step-by-step explanation:

4 0
3 years ago
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ElenaW [278]
Neither A nor B because there is repetition of X values
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Anestetic [448]
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3 years ago
Torrance is shopping for a school party. His donation to the party is snack bags and juice boxes. Snack bags come in packages of
lara [203]

Answer:

Torrance must purchase 5 packages of snack bags and 6 packages of juice boxes.

Step-by-step explanation:

Given that:

Snack bags come in packages of 12.

Juice bags come in packages of 10.

To find:

Fewest number of packages of each product so that there are same number of snack bags and juice boxes.

Solution:

Number of snack bags when 1 package is bought = 12

Number of snack bags when 2 package is bought = 24

Number of snack bags when 3 package is bought = 36

Number of snack bags when 4 package is bought = 48

Number of snack bags when 5 package is bought = 60

Number of snack bags when 6 package is bought = 72

Number of juice bags when 1 package is bought = 10

Number of juice bags when 2 package is bought = 20

Number of juice bags when 3 package is bought = 30

Number of juice bags when 4 package is bought = 40

Number of juice bags when 5 package is bought = 50

Number of juice bags when 6 package is bought = 60

Number of juice bags when 7 package is bought = 70

We can see that when 5 packages of snack bags are bought and 6 packages of juice bags are bought, 60 bags of each are bought.

This can be found by finding the LCM as well.

LCM of 10 and 12 is 60.

It means we need to buy 60 bags of each item.

And we can easily find the number of packages for each.

Number of packages of snack bags to be bought = \frac{60}{12} =5

Number of packages of juice bags to be bought = \frac{60}{10} = 6

Torrance must purchase 5 packages of snack bags and 6 packages of juice boxes.

4 0
3 years ago
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