Answer:
Explanation:
Hello there!
In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:
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Answer:
Explanation:
First, we need to find the molecular mass of water (H₂O).
H₂O has:
Use the Periodic Table to find the mass of hydrogen and oxygen. Then, multiply by the number of atoms of the element.
There are 2 hydrogen atoms, so multiply the mass by 2.
Now, find the mass of H₂O. Add the mass of 2 hydrogen atoms and 1 oxygen atom.
Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.
Multiply. The grams of H₂O will cancel out.
The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.
The 7 in the hundred thousandth place tells us to round up.
There are about <u>0.0018 moles in 0.032 grams.</u>