<span>FeNCS+ product...............thats how you do it i believe </span>
In this case, we are going to assume that there are 100 atoms to make things easier.
Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%
14.0031*(100-R)% + 15.001 * R%= 14.00674
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %
14.0031*(100-R) + 15.001 * R= 14.00674
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648
Then, the abundance of n-15 is 0.3648%
Answer:
0.00013
Explanation:
I'm pretty sure. I first subtracted 1.87 from 2. I got 0.13. The conversion from mL to L is 0.001. I multiplied 0.13 and 0.001 and got <u>0.00013 mL.</u>
Answer:
The molecular formula of an ascenapthalene is 
Explanation:
where,
=Elevation in boiling point = 
Mass of acenapthalene = 0.515 g
Mass of 
= 15.0 g = 0.015 kg (1 kg = 1000 g)
= boiling point constant = 3.63 °C/m
m = molality
Now put all the given values in this formula, we get
Let the molecule formula of the Acenapthalene be ![C_{6n]H_{5n}](https://tex.z-dn.net/?f=C_%7B6n%5DH_%7B5n%7D)
n = 2.0
The molecular formula of an ascenapthalene is
C: plates slipping along a fault
