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trasher [3.6K]
3 years ago
7

How would you balance this equation HCL+BA-->BaCL2+H2

Chemistry
2 answers:
erik [133]3 years ago
7 0
Put a 2 on the HCl.

2HCl+Ba-->BaCl2+H2
nekit [7.7K]3 years ago
5 0

Chemical reaction: HCl + Ba → BaCl₂ + H₂.

Oxidation reaction: Ba⁰ → Ba⁺² + 2e⁻.

Reduction reaction: 2H⁺ + 2e⁻ → H₂⁰.

Balanced chemical reaction: 2HCl + Ba→ BaCl₂ + H₂.

Barium (Ba) change oxidation number from 0 to +2 (lose electrons), barium is oxidized (reducing agent).

Hydrogen change oxidation number from +1 to 0 (gain electrons), it is reduced.

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How to determine intermolecular forces.
den301095 [7]

Answer:

Incase you have H and F and another H and F

7 0
2 years ago
Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241
Mazyrski [523]

Answer:

-767,2kJ

Explanation:

It is possible to sum enthalpies of half-reactions to obtain the enthalpy of a global reaction using Hess's law. For the reactions:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁= −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂= +361.7 kJ

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl (g) ΔH₃= −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄= − 607.9 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅= − 44.0 kJ

The sum of (4) - (2) produce:

6) XCl₄(s) + O₂(g) ⟶ XO₂(s) + 2Cl₂(g) ΔH₆ = ΔH₄ - ΔH₂ = -969,6 kJ

(6) + 4×(3):

7) XCl₄(s) + 2H₂(g) + O₂(g) ⟶ XO₂(s) + 4HCl(g) ΔH₇ = ΔH₆ + 4ΔH₃= -1338,8 kJ

(7) - 2×(1):

8) XCl₄(s) + 2H₂O(g) ⟶ XO₂(s) + 4HCl(g) ΔH₈ = ΔH₇ - 2ΔH₁= -855,2kJ

(8) - 2×(5):

9) XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g) ΔH₉ = ΔH₈ - 2ΔH₅= <em>-767,2kJ</em>

I hope it helps!

6 0
3 years ago
According to current theory, a major reason for bonding is
tatiyna
Covalent bond   a chemical bond formed by two electrons that are shared between two atoms
ionic bond<span>    a chemical bond formed by the electrostatic attraction between ions</span>
metallic bond<span>    a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal</span>
6 0
2 years ago
Read 2 more answers
1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)<br> weigh?
Nimfa-mama [501]

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

7 0
3 years ago
Help please I really really need it now ​
postnew [5]
1. A 2. B 5. B this is all I know hope it helps
5 0
2 years ago
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