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3 years ago

What’s this answer YALL IM STRUGGLING WITH MATH !!

Mathematics

2 answers:

saul85 [17]3 years ago

5 0

Area: 4900

Perimeter: 280

Vitek1552 [10]3 years ago

3 0

Answer: Area = 4,900 Perimeter = 280

Step-by-step explanation:

For area multiply 70 and 70

for perimeter add all sides ( 70+70+70+70)

i don't know what type is.

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Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo

Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2

is all R2 ⇔

$u\neq 0_{R2}$

$v\neq 0_{R2}$

And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to $R^{2x2}$ using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

$A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]$

We used the first vector ''u'' as the first column of the matrix A

We used the second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

$Det(A)=6-p$

We need this determinant to be different to zero

$6-p\neq 0$

$p\neq 6$

The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that $p\neq 6$

We can write : p ∈ IR - {6}

Notice that is $p=6$ ⇒

$u=(3,6)$

$v=(1,2)$

If we write $3v=3(1,2)=(3,6)=u$ , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.

7 0

3 years ago

What are the missing angle measures in triangle ABC?

Finger [1]

we know that

In the right triangle ABC

∠ $A+$ ∠ $B=90$ ------> by complementary angles

Step $1$

Find the measure of angle B

we know that

$tan\ B=\frac{opposite\ side\ angle\ B}{adjacent\ side\ angle\ B}$

in this problem

$opposite\ side\ angle\ B=7in\\ adjacent\ side\ angle\ B=5in$

$tan\ B=\frac{7}{5} \\ \\ B=arc\ tan\frac{7}{5} \\ \\ B=54.5\ degrees$

Step $2$

Find the measure of angle A

$A+B=90\\ A=90-B\\ A=90-54.5\\ A=35.5\ degrees$

therefore

the answer is the option

35.5° and 54.5°

5 0

3 years ago

Read 2 more answers

Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Gnoma [55]

Sum/difference:

Let

$x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}$

This means that

$3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}$

Now, assume that $x$ is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that $x$ was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

$x = -15\sqrt{8}$

if again we assume x to be rational, we have

$\sqrt{8} = -\dfrac{x}{15}$

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0

3 years ago

What is the answer to x? Help ASAP

Brut [27]

Answer:

Step-by-step explanation:

2x + 24° = 4x ( being vertically opposite angles)

4x - 2x = 24°

2x = 24°

x = 24° / 2

x = 12°

Hope it will help :)

3 0

3 years ago

3.) (4 x 9 - 21) \ 3+6^2

nignag [31]

Answer:

Step-by-step explanation:

Given Expression:

(4 x 9 - 21) \ 3+6^2

Multiply 4 and 9 to get 36.

36 - 21 / 3 + 6^2

Subtract 21 from 36 to get 15.

15/3 + 6^2

Divide 15 by 3 to get 5.

5+6^2

Calculate 6 to the power of 2 and get 36.

5+36

Add 5 and 36 to get 41.

3 0

3 years ago