Answer:
The answer is: To accelerate an object <u>the force applied to the object</u> has to increase.
Explanation:
the acceleration of an object <u>increases with increased force</u> and <u>decreases with increased mass.</u>
Mass have no effect for the projectile motion and u want to know the height "h"
first,
find the vertical and horizontal components of velocity
vertical component of velocity = 12 sin 61
horizontal component of velocity = 12 cos 61
now for the vertical motion ;
S = ut + (1/2) at^2
where
s = h
u = initial vertical component of velocity
t = 0.473 s
a = gravitational deceleration (-g) = -9.8 m/s^2
h=[12×sin 610×0.473]+[−9.8×(0.473)2]
u can simplify this and u will get the answer
h=.5Gt2
H=1.09m
The number 3252.6 has 5 significant figures
