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3 years ago

Started a new ixl and i have no idea how to do this

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

Answer:

y = - $\frac{1}{6}$ x - $\frac{8}{9}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Rearrange 3x + 18y = - 16 into this form

Subtract 3x from both sides

18y = - 3x - 16 ( divide all terms by 18 )

y = - $\frac{3}{18}$ x - $\frac{16}{18}$ , that is

y = - $\frac{1}{6}$ x - $\frac{8}{9}$ ← in slope- intercept form

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You are determining the mass of an object using a triple beam balance. When the pointer is lined up with the zero mark, the ride

Molodets [167]

328 grams is the mass.

3 0

2 years ago

castortr0y [4]

Answer:

Its an Arithmetic progression

Step-by-step explanation:

d1= -18-(-25)= 7

d2= -11-(-18)= 7

d1 = d2

r1 = -18/25=0.72

r2 = -11/-8= 0.611

r1 isnt = r2

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2 years ago

A carpenter is putting a skylight in a roof. If the roof measures 10 + 8 by 8 + 6 and the skylight measures + 5 by 3 + 4, what i

Usimov [2.4K]

Answer:

The area is: $77x^2 + 105x + 28$ , option b.

Step-by-step explanation:

Rectangular area:

The area of a rectangular space is given bt the multiplication of its measures.

Area of the roof:

Dimensions of 10x + 8 and 8x + 6. So

$A_{r} = (10x+8)(8x+6) = 80x^2 + 60x + 64x + 48 = 80x^2 + 124x + 48$

Area of the skylight:

Dimensions of x + 5 and 3x + 4. So

$A_{s} = (x+5)(3x+4) = 3x^2+4x+15x+20 = 3x^2 + 19x + 20$

What is the area of the remaining roof after the skylight is built?

Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So

$A_{r} - A_{s} = 80x^2 + 124x + 48 - (3x^2 + 19x + 20) = 80x^2 - 3x^2 + 124x - 19x + 48 - 20 = 77x^2 + 105x + 28$

The area is: $77x^2 + 105x + 28$ , option b.

3 0

2 years ago

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

Lemur [1.5K]

Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

5 0

3 years ago

Read 2 more answers

Factor the expression below using the greatest common factor 6p3- 2p2 - 8p

miss Akunina [59]

Answer:

The Factor of expression using the greatest common factor is $2p(3p^2- p-4)$

Step-by-step explanation:

Consider the provide expression.

$6p^3- 2p^2 - 8p$

We need to Factor the expression using the greatest common factor.

First look at the coefficients of the variable.

The coefficients are the factor of 2.

Variable p is the greatest common factor in the provided expression.

$2p\times 3p^2- 2p\times p- 2p\times 4$

$2p(3p^2- p-4)$

Hence, the Factor of expression using the greatest common factor is $2p(3p^2- p-4)$ .

7 0

3 years ago