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klio [65]
3 years ago
6

A publisher requires 2∕3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest

whole page, how many pages of the magazine are advertisements?
Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

\boxed{13} pages

Step-by-step explanation:

Divide the total number of pages by 5 to get how many sets of every 5 pages will contain 2/3 of a page of advertisements.

\frac{98}{5} = 19.6

Multiply this value by \frac{2}{3} to get the total number of pages.

19.6 * \frac{2}{3} \approxeq 13 pages

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Answer:

^{(x-y)}C_{10}=\frac{(x-y)!}{10! \times (x-y-10)!}

Step-by-step explanation:

Total flavors Sammy initially had = x

Number of flavors Sammy throw away = y

After throwing away y flavors, the number of flavors Sammy will be left with = x - y

He needs to make 10-flavor bags from these (x - y) flavors. In order words he needs to chose 10 flavors for each bag from(x - y) flavors. The order of selection is not important here, so this is a problem of combinations. Also since we have to make selections or small groups, this also indicates that we have to use combinations.

So we need to make combinations of 10 flavors from a total of (x - y) flavors. This can be represented as ^{(x-y)}C_{10}

The formula for combinations is:

^{n}C_{r}=\frac{n!}{r!(n-r)!}

Using the values in this formula, we get:

^{(x-y)}C_{10}=\frac{(x-y)!}{10! \times (x-y-10)!}

7 0
3 years ago
(PHOTO) Please help me need this done by tomorrow thank you.​
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Answer:

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7 0
2 years ago
Trevor Sherr is paid $1.20 for each hand-painted
Margarita [4]

Answer:

$112.80

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8 0
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yuradex [85]

Answer:

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Best regards

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i hope this helped!!

7 0
3 years ago
Read 2 more answers
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