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3 years ago

What is the area of this triangle?

Mathematics

2 answers:

kari74 [83]3 years ago

8 0

Answer:

The area of the triangle is 24 units2

Step-by-step explanation:

To find an area of a triangle you simply have to multiply a and b which are the legs of a triangle, in this case it would be 6 and 8, after doing that you divide the result by 2. So A= 6x8/2 ---> A=48/2 -----> A=24

mafiozo [28]3 years ago

5 0

Answer:

I believe the answer is 24

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-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$

Step-by-step explanation:

$-6-3\left(2x+4\right)=18$

Add 6 to both sides:

$-6-3\left(2x+4\right)+6=18+6$

$-3\left(2x+4\right)=24$

Divide both sides by -3:

$\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}$

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$2x+4-4=-8-4$

$2x=-12$

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7 0

3 years ago

Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .

anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

$tan (x) =\frac{sin(x)}{cos(x)}$

So we can replace into our formula and we got:

$tan(x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We have the following identities useful for this case:

$sin(a-b) = sin(a) cos(b) - sin(b) cos(a)$

$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

And this identity is satisfied for all:

$(x-y) \neq \frac{\pi}{2} +n\pi$

8 0

3 years ago