Answer:
Explanation:
The gas ideal law is
PV= nRT (equation 1)
Where:
P = pressure
R = gas constant
T = temperature
n= moles of substance
V = volume
Working with equation 1 we can get
The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.
or
(equation 2)
The cylindrical container has a constant pressure p
The volume is the volume of a cylinder this is
Where:
r = radius
h = height
(pi) = number pi (3.1415)
This cylinder has a radius, r and height, h so the volume is
Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:
Replacing these values in the equation 2 we get:
(equation 2)
The complete question; At atmospheric pressure a balloon contains 2.00 l of nitrogen gas, how would the volume change if the kelvin temperature was only 75 % of its original value?
The change in volume would be;
original volume × percentage
= 2 ×0.75 = 1.5 L
Thus the volume would change by 1.5 L
<u>Gay lussas law:</u>
Gay-Lussac law states that the pressure for a given gas’ mass changes directly to an absolute gas temperature, provided that the volume held to be constant. The mathematical expressions of Gay-Lussac law also correspond to those of Charles Law:
This gas law is important because it shows that an increase in gas temperature increases the pressure proportionally (if the volume does not change). Similarly, as the temperature decreases, the pressure decreases proportionally.
Answer:
P₂ = 2.60 atm
Explanation:
Given data:
Initial pressure = 2.38 atm
Initial temperature = 25.0 °C
Final pressure = ?
Final temperature = 52.78°C
Solution:
Initial temperature = 25.0 °C (25.0+273 = 298 K)
Final temperature = 52.78°C (52.78+273 = 325.78 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
2.38 atm / 298 K = P₂/325.78 K
P₂ = 2.38 atm × 325.78 K / 298 K
P₂ = 775.35 atm. K /293 K
P₂ = 2.60 atm