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3 years ago

Hi! Can I please have help on solving linear graphing problems?

Mathematics

1 answer:

ElenaW [278]3 years ago

6 0

Answer:print out starter sheets

Step-by-step explanation:

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Find the coordinates of the midpoint of HX given that H(-1,3) and X(7,-1).

Elis [28]

A. find the average of both x's for the x value, and the average of both y's for the y value. (-1+7)=3 (3+(-1))=1

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3 years ago

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Plsss anybody help no links more files they are viruses

mr_godi [17]

Answer:

1- B & C (Same answer and also I'm not that sure)

2- B: y = 8x (I'm sure of this ^^)

3- Option 3

4- 108 degrees

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2 years ago

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Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

This is a parabola (0,2.5) and turns upside down.

4 0

3 years ago

Please help meeeee it’s actually super easy

rewona [7]

The area for that shape should be 28 because 20+8=28! Hope this helps.

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2 years ago

Graph of g(x) = x2 − 5

Brut [27]

Answer: 6rx = x^2 -5

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2 years ago