A drag because the lift keeps it up and the drag brings it down
Answer:
a) Time interval between signals according to an observer on spaceship A = 1.09h
b) Time interval between signals according to an observer on spaceship B = 1.09h
c)The speed of A relative to the station to measure a time interval of 2.00h = 2.6 * 10⁸ m/s
Explanation:
a) Time interval between signals according to an observer on spaceship A
Initial time intervals for the alert signal, Δt₀ = 1.00h
The speed of spaceship A, v = 0.400c
The formula for the time interval is given by
Δt = ∆t₀ /√(1-(v/c)² )
Δt = 1 / √(1-(0.4c/c)² )
Δt = 1 / √(1-(0.4)²
Δt = 1.09 h
b) The intervals between signals according to an observer on spaceship A and B are equal because both spaceships are moving at the same speed.
Therefore, the time interval between signals according to an observer on B is Δt = 1.09 h
c) The speed of A relative to the station to measure a time interval of 2.00h
Δt = ∆t₀ /√(1-(v/c)² )
2 = 1 /√(1-(v/c)² )
√(1-(v/c)² ) = 0.5
1-(v/c)² = 0.25
0.75 = (v/c)²
v/c = 0.866
v = 0.866c
v = 0.866 * 3 * 10⁸
v = 2.6 * 10⁸ m/s
I'm assuming you want the first law of thermodynamics.
The First Law of Thermodynamics states that heat is a form of energy and cannot be created or destroyed. It can, however, be transferred from one location to another and can be converted into other forms of energy.
Answer:
20m
Explanation:
The two tens cancel each other out, as they are in opposite directions. Now we only care about the 20m, which if we have no 10's, will end up 20m away.
