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Evgesh-ka [11]
3 years ago
11

Sal connected four light bulbs in a parallel circuit. If Sal adds another light bulb, what is true about the current in each bul

b?
A) The current decreased when a fourth bulb was added.

B) The current in the four bulbs is much less than the current in three bulbs.

C) The current in each bulb remained the same even though another bulb was added.

D) The current in the fourth bulb is less than the current int he other three bulbs.
Physics
2 answers:
Zinaida [17]3 years ago
4 0

The answer is C) The current in each bulb remained the same even though another bulb was added.

kolbaska11 [484]3 years ago
4 0

Since all the bulbs are connected in parallel with each other

so here voltage across each bulb will remains the same

so here we will have

V = i R

now all bulbs are identical and we have same voltage source across all the bulbs

so we will have current in each bulb given by same equation

i = \frac{V}{R}

now we can say that correct answer will be

C) The current in each bulb remained the same even though another bulb was added.

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platform diving in the olympic games takes place at two heights: 5 meters and 10 meters. What is the velocity of a diver enterin
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1) Velocity: 9.9 m/s and 14 m/s

The motion of the diver is a free-fall motion, so it is a uniform accelerated motion. Choosing downward as positive direction, the final velocity can be found by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u = 0 is the initial velocity (the diver starts from rest)

a=g=9.8 m/s^2 is the acceleration of gravity

s is the displacement

For the diver jumping from 5 m, s = 5 m, so

v=\sqrt{2as}=\sqrt{2(9.8)(5)}=9.9 m/s

For the diver jumping from 10 m, s = 10 m, so

v=\sqrt{2as}=\sqrt{2(9.8)(10)}=14 m/s

2) Time: 1.01 s and 1.43 s

The time of flight of each diver can be found by using the other suvat equation

s=ut+\frac{1}{2}at^2

And since u = 0, it can be reduced to

s=\frac{1}{2}at^2

For the diver jumping from 5 m, s = 5 m, so we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(5)}{9.8}}=1.01 s

For the diver jumping from 10 m, s = 10 m, so we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(10)}{9.8}}=1.43 s

5 0
3 years ago
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