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Evgesh-ka [11]
3 years ago
11

Sal connected four light bulbs in a parallel circuit. If Sal adds another light bulb, what is true about the current in each bul

b?
A) The current decreased when a fourth bulb was added.

B) The current in the four bulbs is much less than the current in three bulbs.

C) The current in each bulb remained the same even though another bulb was added.

D) The current in the fourth bulb is less than the current int he other three bulbs.
Physics
2 answers:
Zinaida [17]3 years ago
4 0

The answer is C) The current in each bulb remained the same even though another bulb was added.

kolbaska11 [484]3 years ago
4 0

Since all the bulbs are connected in parallel with each other

so here voltage across each bulb will remains the same

so here we will have

V = i R

now all bulbs are identical and we have same voltage source across all the bulbs

so we will have current in each bulb given by same equation

i = \frac{V}{R}

now we can say that correct answer will be

C) The current in each bulb remained the same even though another bulb was added.

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Nonconjugated β,γ-unsaturated ketones are in base-catalyzed equilibrium with their conjugated α,β-unsaturated isomers. The mecha
Viefleur [7K]

Answer:

Explanation:

The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated β, γ- unsaturated ketones, like 3-cyclohexanone to their conjugated α, I²- unsaturated isomers.

Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an α- hydrogen from the protonated 3-cyclo hexanone to yield ethanol

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Answer:

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6 0
3 years ago
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8 0
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A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
ElenaW [278]

Explanation:

The given data is as follows.

    Length of beam, (L) = 5.50 m

    Weight of the beam, (W_{b}) = 332 N

     Weight of the Suki, (W_{s}) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

                 \sum M_{o} = 0

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                x = \frac{W_{b} \times 1.5}{W_{s}}

                   = \frac{332 N \times 1.5}{505 N}

                   = 0.986 m

Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

8 0
3 years ago
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