The acceleration of the boat is
(eastward)
Explanation:
We can solve this problem by using Newton's second law, which states that:
F = ma (1)
where
F is the net force on a body
m is its mass
a is its acceleration
First of all, we have to find the net force acting on the boat. We have:
- The force of the motor, 100 N eastward
- The force of the air resistance, 60 N westward
So the net force is:
F = 100 N - 60 N = 40 N (eastward)
Now we can apply eq.(1), using:
F = 40 N
m = 20 kg (mass of the boat)
and solving for a, we find the acceleration:

And the direction is the same as the net force (eastward).
Learn more about acceleration and Newton laws of motion:
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There are two force acting on an object that is being lifted. (1) the weight of the car, (2) the upward force. The difference of these force should be equal to the product of the mass and the acceleration. (This is the content of Newton's 2nd Law of Motion). If we let the lifting force be F,
F - (830)(9.8) = (830)(3.8)
The value of F from the equation is 11288 N.
C volume because the volume take up the Mater and space around it thing
Answer:
Solution given:
height [H]=25m
initial velocity [u]=8.25m/s
g=9.8m/s
now;
a. How long is the ball in flight before striking the ground?
Time of flight =?
Now
Time of flight=
substituting value
- =

- =2.26seconds
<h3>
<u>the ball is in flight before striking the ground for 2.26seconds</u>.</h3>
b. How far from the building does the ball strike the ground?
<u>H</u><u>o</u><u>r</u><u>i</u><u>z</u><u>o</u><u>n</u><u>t</u><u>a</u><u>l</u><u> </u>range=?
we have
Horizontal range=u*
<h3>
<u>The ball strikes 18.63m far from building</u>. </h3>