Answer:
a = - 1.987 × 10⁶ ft/s²
t = 6.84 × 10⁻⁴ s
Explanation:
v₀ = 910 ft/s
x = 5 in.
relation v = v₀ - k x
v = 0 as body comes to rest
0 = 900 - 5k/12
k = 2184 s⁻¹
acceleration
where
(A) a = -k × v
at v= 910 ft/s
a = - 1.987 × 10⁶ ft/s²
(B) at x = 3.9 in.
v = 910 - 3.9(2184)/12
v = 200.2 m/s
t = 6.84 × 10⁻⁴ s
Answer:
Continuous random variable
Explanation:
The distance that baseball travels after being hit is a random variable and it assume any real value defined on the sample space.
The distance is measurable and thus is continuous random variable because continuous variable cannot be counted but could be measured.
You have to divide the distance by the work. So,
55/5
=11
So, she used 11 N of force to lift her cat.
Answer: The charge that flows during the change is 0.2C
Explanation: Please see the attachments below
Answer:
Explanation:
The balance condition, to keep the gate from moving, requires that the net torque be zero, this is, the torques on both sides of the gate must be equal.
- Torque equation: τ = F × d
a) <u>Torque applied by one of the children:</u>
b) <u>Torque applied by the second child</u>:
c) <u>Equilibrium condition</u>:
- τ₁ = τ₂
- 170 N × 0.590m = F × 0.430m
- F = 170 N × 0.590 m / 0.430 m = 233 N ← answer