The answer would be C.) prices of related goods
Inverse square law:
where
is the intensity at distance 1
is the intensity at distance 2
is distance 1
is distance 2
The inverse squared law state that intensity decreases in inverse proportion to the distance squared. So if light obeyed that rule, it will decreases its intensity as the square of the distance increases.
We can conclude that the correct answer is:
true.
I think it's velocity, because when an object stands in inertia, or it has velocity equals to zero, or it has constant velocity because there is no friction to stop the object.
Answer:
x = ½ aw t²
x = d − ½ az t²
Explanation:
The position of each car at time t is:
x = x₀ + v₀ t + ½ at²
For car W:
x = 0 + (0) t + ½ aw t²
x = ½ aw t²
For car Z:
x = d + (0) t + ½ (-az) t²
x = d − ½ az t²
Solving the system of equations for x will give us the location the cars meet (relative to car W's starting point).