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IrinaK [193]
3 years ago
6

Which statement about the density of warm water is most likely correct?

Chemistry
1 answer:
Damm [24]3 years ago
3 0
Density is a property of a material which describes the mass of a material per unit volume. Density is said to be slightly dependent on temperature. We look at the density of water at different temperatures:
<span>
100 </span>°C: 958.4 kg/m^360 °C: 983.2 kg/m^320 <span>°C</span>: 998.2 kg/m^3

Therefore, warm water has a lower density than water in colder temperature.
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The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per uni
Nataliya [291]

Answer:

Explanation:

turn over number = R max / [E]t   = K2

From given , R max = 249 * 10 ^ -6 mol. L^-1

T [E]t = 2.23 n mol. L^-1

           =   2.23 * 10^-9 mol. L^-1

Putting values in above equation,

=          111.65 * 10^3           S^-1

Turn over number is maximum no of substrate molecule that can be converted into product molecules for unit time by enzyme molecule.

5 0
3 years ago
Hi! Which of the following decreases kinetic energy of solvent molecules? ( I need this handed in quickly!)
Black_prince [1.1K]

Answer:

c

Explanation:

4 0
3 years ago
Can you please help me !!
ioda

Answer:

Explanation:

A)  O2 (non polar covalent)

B)  HF  (polar covalent)

C) NaCl (because its ionic)

im not 100% sure hope it helps

7 0
3 years ago
.Which of the following is true about elements?
Ludmilka [50]

Answer:

C

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6 0
3 years ago
Read 2 more answers
You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol
defon

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀\frac{[A^{-}]}{[HA]}

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀\frac{[A^{-}]}{[HA]}

1,38 = \frac{[A^{-}]}{[HA]} <em>(1)</em>

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] <em>(2)</em>

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid  ≡ 0,15 moles of acetic acid ×\frac{60,05 g}{1mol} = <em>9,0 g of acetic acid</em>

<em></em>

I hope it helps!

5 0
3 years ago
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