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vaieri [72.5K]
4 years ago
10

Explain why it works to break apart a number by place values to multiply

Mathematics
1 answer:
lora16 [44]4 years ago
4 0
Breaking Apart Strategy is an easy way to find multiplication, even though those are difficult ones. This is a great strategy for breaking apart harder multiplication problems, so the result you get is the same as if you are multiplying the original equation.
<span>
For example, suppose you want to get this multiplication:

</span>8\times 7
<span>
So eight times seven is a tricky one sometimes. Maybe we forget this multiplication so let's break it apart. Therefore, let's break apart seven, that is:

</span>7=5+2
<span>
This is true because five and two makes seven. Therefore, the new equation is:

</span>8(5+2)
<span>
Applying distributive property:

</span>8\times 5+8\times2=40+16=56
<span>
So:

</span>8\times 7=56

<span>As you can see the multiplication was obtained in a easy way.
 
</span>
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HURRY I NEED HELP!!!<br> Distribute the expression<br> }(2n + 6 - 48y)
zepelin [54]

Answer:

2(n+3-24y)

Step-by-step explanation:

hope this helps!

8 0
3 years ago
What is 5x = ____. If x = 2.5,
Gelneren [198K]

Step-by-step explanation:

x = 2.5

5x

5 × 2.5

12.5

5x = <u>12.5</u>...

6 0
3 years ago
Read 2 more answers
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]​
Alekssandra [29.7K]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
If the translation T maps point A(7,2) onto point A′(5,5), what is the translation T?
VMariaS [17]

Answer:

< - 2, 3 >

Step-by-step explanation:

To translate from A(7, 2) to A'(5, 5 )

There is a shift of - 2 units in the x- direction and a shift of + 3 units in the y- direction.

That is (x, y ) → (x - 2, y + 3 ) ← translation rule, or

The translation is < - 2, 3 >

5 0
4 years ago
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