Which of the following are NOT enclosed by a cell wall.

Buffering capacity refers to: the effectiveness of commercial antacids the extent to which a buffer solution can counteract the

kirill [66]

Answer: Option (b) is the correct answer.

Explanation:

Buffere is defined as the solution to whom when an acid or base is added then it resists any in change in pH of the solution.

This is because a buffer has the ability to not get affected by the addition of small amounts of an acid or a base. So, basically it keeps the concentration of both hydrogen ions and hydroxides equal. As a result, it helps in maintaining the pH of the solution.

And, the capacity of a buffer solution to resist the change is known as buffer capacity.

Thus, we can conclude that buffering capacity refers to the extent to which a buffer solution can counteract the effect of added acid or base.

8 0

3 years ago

Describe what happens when you take a antacid

lesya [120]

The antacid is alkaline so it neutralizes the excess acids in your stomach.

3 0

3 years ago

How much heat is absorbed by 15.5g of water when it's temperature is increased from 20.0C the specific heat of the water is 4.18

Anuta_ua [19.1K]

Hello!

The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):

$Q=m*C* \Delta T=15,5 g * 4,184 (J/g^\circ C) * 20 ^\circ C=1297,04 J$

So, the Heat absorbed by water is 1297,04 J

Have a nice day!

7 0

3 years ago

A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number

Cloud [144]

Answer : The distance covered by slow snail in 24 hours is $3.2\times 10^{13}pm$

Explanation :

As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

= 1440 minutes

Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

= 3168 cm

= $3.2\times 10^3cm$

Now we have to convert 'cm' into 'pm'.

Conversion used : $1cm=10^{10}pm$

As, $1cm=10^{10}pm$

So, $3.2\times 10^3cm=\frac{3.2\times 10^3cm}{1cm}\times 10^{10}pm=3.2\times 10^{13}pm$

Therefore, the distance covered by slow snail in 24 hours is $3.2\times 10^{13}pm$

4 0

3 years ago

If atoms are so tiny how do we know they exist

Aleksandr [31]

There are three ways that scientists have proved that these sub-atomic particles exist. They are direct observation, indirect observation or inferred presence and predictions from theory or conjecture. Scientists in the 1800's were able to infer a lot about the sub-atomic world from chemistry.

5 0

2 years ago