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Irina18 [472]
3 years ago
10

Which of the following procedures was done to minimize human error? We let the weight swing 25 times and divided by 25 to get th

e avg period of one oscillation Why did we plot T2 vs L instead of just T vs L? By squaring the entire equation, we make T2 linear with L. Suppose Sarah Smith is swinging on a swing at the park. If the chain is 3 meters long, what will be the period (time) of one swing? 3.47 seconds 4.2 seconds 2.8 seconds Should the period depend on the mass at the end of the string?
Physics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

T = 3.475 s

Time period is independent from mass

Explanation:

- To reduce the human error in taking any measurements we take multiple N number of readings. Then sum up all the readings and divide by N to find an average. The error between each individual reading and the actual reading is reduced by repetition.

- We use the plot of T^2 against L to form a linear relationship between two variables. We square the entire the equation for linearize the equation.

- Given, L = 3 m . The time period is approximated by a pendulum expression given as:

                                     T = 2*pi*sqrt ( L / g )

Where, g is the gravitational acceleration 9.81 m/s^2

- Then we have:

                                     T = 2*pi*sqrt ( 3 / 9.81 )

                                     T = 3.475 s

- From above expression we see that time period is independent from the mass at the end of the string but a function of pendulum geometry and kinetics.  

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Lila is using a Bunsen burner. She has all of her chemicals on her workstation. Which would be the best lab practice?
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<span>
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A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin
lyudmila [28]
Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
W= \int\limits^{0.540m}_{0} {F} \, dx =  \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =
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By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
W=16000(0.540m)+10000  \frac{(0.540m)^2}{2} - 26000  \frac{(0.540m)^3}{3}  =
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part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
W=16000(0.95m)+10000  \frac{(0.95m)^2}{2} - 26000  \frac{(0.95m)^3}{3}  =
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5 0
3 years ago
How does the gravitational force between two objects change if the distance between the objects doubles?
Ymorist [56]

if the distance between the objects is doubled the force is reduced by a factor of 4

<h3>Whats is gravitational force?</h3>

Gravitational force is the force of attraction between objects in the universe.

f = G * m1 * m2 / r^2

f = gravitational force

G = gravitational constant

m1 = mass of object 1

m2 = mass of object 2

r = distance between the objects

From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4

Therefore: The force decreases by a factor of 4.

hope it helps

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2 years ago
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